You apply the sum of interior angles formula ie. (n-2)180. n=number of sides
since a pentagon has 5 sides it will be (5-2)180=540.
now add everything. x-5+x-6+2x-7+x+2x-2=540.
Solve for x: 7x-20=540
7x=540+20
7x=560
x=560/7
x=80
243.875 rounded to the nearest tenth is...... 243.9 :)
243.875 rounded to the nearest hundredth is ...... 243.88 :)
243.875 rounded to the nearest ten is ...... 240 :)
243.875 rounded to the nearest hundred is ......200 :)
thank you for the question and hopefully this helped you :)
So,
We need to convert the gallons into cups.
1 gal. = 16 c.
2 3/4 gal. = 2(16) + 3/4(16) = 32 + 12 = 44
3 5/8 gal. = 3(16) + 5/8(16) = 48 + 10 = 58
5 gal. = 5(16) = 80
There are 20 + 15 = 35 people. Therefore, Bob's friends will drink a total of 35 cups of lemonade, 35 cups of punch, and 35 cups of soda. We just need to subtract these amounts from what Bob has.
44 - 35 = 9 cups of lemonade
58 - 35 = 23 cups of punch
80 - 35 = 45 cups of soda
Obviously, then, Bob will have enough drinks.
He has 9 cups of lemonade, 23 cups of punch, and 45 cups of soda left over. In gallons, he has 9/16 gallons of lemonade, 1 7/16 gallons of punch, and 2 13/16 gallons of soda left over.
Answer:
it is the butt-tox y in this equation and my peepee hole says it smells in the graph so nice poopy job random person!!!!!!!????
Answer:
Step-by-step explanation:
1)
Percentile is related to the area under the standard normal curve to the LEFT of a certain data value (which in this case would be 26.1 inches).
On my Texas Instruments TI-83 Plus calculator, I found this area as follows:
normcdf(-100, 26.1, 28.4,1.2), where the range -100 to 26.1 represents the area (as a decimal fraction) to the left of 26.1 inches. My result was 0.028, which corresponds to the 3rd percentile (0.028 rounds off to 0.03, which would be 3rd percentile).
2) The mean waist size is 28.4 inches, represented by a vertical line through the standard normal curve lying between 24 and 32. We use the same function on the calculator: normcdf(24, 32, 28.4, 1.2).
The result is 0.9985. Subtracting this from 1.0000, we get 0.001, or 0.1%, which is the percentage of female soldiers requiring custom uniforms.
