All categories

3 years ago

What kind of graph would use for this data? The months of the year and the amount of rainfall, and why

Chemistry

1 answer:

Digiron [165]3 years ago

6 0

Answer:

A Desert Climatogram is a graph that shows the temperature and rainfall, for each month in the year, for the Desert.

Explanation:

You might be interested in

Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 3.50 moles of magnesium

Firdavs [7]

Answer:

$n_{Mg}=3.50molMg\\\\ n_{Cl}=7.00molCl\\\\n_O=28.0molO$

Explanation:

Hello there!

In this case, according to the given information it turns out possible for us to realize that one mole of the given compound, Mg(ClO₄)₂, has one mole of Mg, two moles of Cl and eight moles of O; thus, we proceed as follows:

$n_{Mg}=3.50molMg(ClO_4)_2*\frac{1molMg}{1molMg(ClO_4)_2}=3.50molMg\\\\ n_{Cl}=3.50molMg(ClO_4)_2*\frac{2molCl}{1molMg(ClO_4)_2}=7.00molCl\\\\n_O=3.50molMg(ClO_4)_2*\frac{8molO}{1molMg(ClO_4)_2}=28.0molO$

Best regards!

3 0

3 years ago

Write a balanced equation for the following:

Ket [755]

(ANS1)— P4 + 5O2 ---> 2P2O5

(ANS2)— C3H8 + 5O2---> 3CO2 + 4H20

(ANS3)— Ca2Si + 4Cl2 ---> 2CaCl2 + SiCl4

7 0

3 years ago

Nitrogen effuses through a pinhole 1.7 times as fast as another gaseous element under the same conditions. Estimate the other el

marysya [2.9K]

Answer:

80.92, Krypton

Explanation:

What is effusion?

• It is a process where gas escapes through a pinhole (a very small hole) into a region of low pressure or vacuum

Graham's law of effusion of gas

• states that at a given constant temperature and pressure, the rate of effusion of gases is inversely proportional to the square root of their molar masses

$\boxed{ \frac{Rate_1}{Rate_2} = \sqrt{ \frac{M_2}{M_1} } }$

Calculations

Nitrogen exist as N₂ at room temperature, thus its molar mass is 2(14)= 28.

Let the rate and molar mass of unknown gas be Rate₂ and M₂ respectively.

Since N₂ effuses 1.7 times as fast as the unknown gas,

Rate₁= 1.7(Rate₂)

$\frac{Rate_1}{Rate_2} = 1.7$

$1. 7 = \sqrt{ \frac{M_2}{28} }$

Square both sides:

$2.89 = \frac{M_2}{28}$

Multiply both sides by 28:

2.89(28)= M₂

M₂= 80.92

Identity of gas

The molar mass of 80.92 lies between Bromine and Krypton. However since Bromine exist as Br₂, the value of it's molar mass would be 159.8 instead. Hence, Bromine is eliminated.

If the gas is a diatomic element, the atomic weight is 80.92 ÷2= 40.46. Thus, we are now considering if Argon could be its identity. However, Argon is a noble gas and will not exist as a diatomic element. Argon is therefore eliminated too.

Thus based on the above reasoning, its probable identity is Krypton.

7 0

3 years ago

In the important industrial process for producing ammonia (the Haber Process), the overall reaction is:

Kisachek [45]

Answer:

Explanation:

Here we have to use stoichiometry.

First of all, we have to calculate the mass of 100% of yield:

1.7 g ------- 98%

X -------- 100%

X = 1.73 g (approximately)

Second, we have to calculate the mass of N2 that is necessary to react to produce the mass of 1.73g of NH3. To do that, we have to use the Molar mass of N2 and NH3 and don't forget the stoichiometric relationship between them.

Molar Mass N2 : 14x2 = 28 g/mol

Molar Mass NH3: 14 + 3 = 17 g/mol

28g (N2) ------- 17x2 (NH3)

X ------------ 1.73 g

X = 1.42 g (approximately)

5 0

3 years ago

For the reaction NH3 + NO → N2 + H2O, identify the reactants, products, and their coefficients once the equation is balanced. (3

nirvana33 [79]

Answer:

option C = Reactant: 4NH₃ + 6NO → product: 5N₂ + 6H₂O

Explanation:

Chemical equation:

NH₃ + NO → N₂ + H₂O

Balanced chemical equation:

4NH₃ + 6NO → 5N₂ + 6H₂O

Ammonia is react with nitrogen mono oxide and produced nitrogen and water.

Ammonia and nitrogen monoxide are reactants while water and nitrogen are product.

Four number of moles of ammonia react with six nitrogen monoxide and produced five mole of nitrogen and six mole of water.

3 0

3 years ago