Answer:
B
Step-by-step explanation:
Angle M is vertical to K, it is congruent. Angle E and C are corresponding angles to Angle M, which are angles positioned in the same direction. Angle E and C are congruent because they are the congruent to Angle M and Angle M is congruent to Angle K.
let's recall that on the IV Quadrant the x/cosine is positive and the y/sine is negative, and of course the hypotenuse is just a radius unit and therefore never negative.
![\bf \pm\sqrt{15^2-(-7)^2}=a\implies \pm\sqrt{176}=a\implies \stackrel{\textit{IV Quadrant}}{+\sqrt{176}=a} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill cos(\theta )=\cfrac{\stackrel{adjacent}{\sqrt{176}}}{\stackrel{hypotenuse}{15}}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cpm%5Csqrt%7B15%5E2-%28-7%29%5E2%7D%3Da%5Cimplies%20%5Cpm%5Csqrt%7B176%7D%3Da%5Cimplies%20%5Cstackrel%7B%5Ctextit%7BIV%20Quadrant%7D%7D%7B%2B%5Csqrt%7B176%7D%3Da%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20cos%28%5Ctheta%20%29%3D%5Ccfrac%7B%5Cstackrel%7Badjacent%7D%7B%5Csqrt%7B176%7D%7D%7D%7B%5Cstackrel%7Bhypotenuse%7D%7B15%7D%7D~%5Chfill)
I don’t see any statement options to be able to answer this question.
The solution to the inequality is -20.8 > p (imagine the symbol is the symbol for at least)
Answer:
b
Step-by-step explanation:
