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Natasha2012 [34]
3 years ago
14

A grocery store recently sold 12 cartons of yogurt, of which 2 were peach. if the store sells 18 cartons of yogurt tommorrow, pr

edict how many of the yogurts will be peach.
Mathematics
1 answer:
marusya05 [52]3 years ago
6 0
Tomorrow the grocery store will sell 3 cartons of peach yogurt.
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Find the value of the determinant.
anastassius [24]

Answer:33

Step-by-step explanation: i just did the problem

4 0
4 years ago
Evaluate the difference quotient for the given function.
kherson [118]

Assuming you mean f(t) = g(t) × h(t), notice that

f(t) = g(t) × h(t) = cos(t) sin(t) = 1/2 sin(2t)

Then the difference quotient of f is

\dfrac{\frac12 \sin(2(t+h)) - \frac12 \sin(2t)}h = \dfrac{\sin(2t+2h) - \sin(2t)}{2h}

Recall the angle sum identity for sine:

sin(x + y) = sin(x) cos(y) + cos(x) sin(y)

Then we can write the difference quotient as

\dfrac{\sin(2t)\cos(2h) + \cos(2t)\sin(2h) - \sin(2t)}{2h}

or

\boxed{\sin(2t)\dfrac{\cos(2h)-1}{2h} + \cos(2t)\dfrac{\sin(2h)}{2h}}

(As a bonus, notice that as h approaches 0, we have (cos(2h) - 1)/(2h) → 0 and sin(2h)/(2h) → 1, so we recover the derivative of f(t) as cos(2t).)

7 0
3 years ago
Who can help me ! <br> .... thanks
Tasya [4]
Given that there is no any option to choose I am going to help you according to the concepts of Congruent Triangles. Two triangles are congruent if and only if:

1. They have:exactly the same three sides
2. exactly the same three angles.

<span>There are five ways to find if two triangles are congruent but in this problem we will use only two.


First Answer:

<u>ASA criterion:</u> </span><em>A</em><span><em>ngle, side, angle</em>. This means that we have two triangles where we know two angles and the included side are equal.</span>

So:

If ∠BAC = ∠DEF and \overline{AC}=\overline{DE}

<em>Then ΔABC and ΔEFD are congruent by ASA criterion.</em>

Second answer:

<u>SAS criterion:</u> <em>S</em><span><em>ide, angle, side</em>. This means that we have two triangles where we know two sides and the included angle are equal.
</span>
If \ \overline{AC}=\overline{DE} \ and \ \overline{BC}=\overline{DF}

<em>Then ΔABC and ΔEFD are congruent by SAS criterion.</em>

4 0
3 years ago
Help me. I don't understand. Please help me find X and IK
sertanlavr [38]

Answer:

x=4\\\\y=6\\\\IK=47

Step-by-step explanation:

Two Tangent Theorem: Tangents which meet at same point are equal in length.

Here tangents at J and H meet at I.

Hence\ HI=IJ\\\\y^2-10=4y+2\\\\y^2-4y-12=0\\\\y^2-6y+2y-12=0\\\\y(y-6)+2(y-6)=0\\\\(y-6)(y+2)\\\\y\ can\ not\ be\ negative\ as\ in\ that\ case\ IJ\ will\ be\ negative.\\\\Hence\ y=6\\\\IJ=4y+2=4\times 6+2=26\\\\\\\\Tangents\ at\ J\ and\ L\ meet\ at\ K.\ Use\ two\ tangent\ theorem.\\\\JK=KL\\\\5x+1=6x-3\\\\6x-5x=1+3\\\\x=4\\\\JK=5x+1=5\times 4+1=21\\\\\\IK=IJ+JK=26+21\\\\IK=47

6 0
3 years ago
Rectangle A has 7 times the area of rectangle
krok68 [10]
Wa=0.5Wb, Ha=20, Hb is unkown
the area of rectangle a is : Wa*20
the area of rectangle b is : Wb*Hb
Rectangle a has 7 times the area of rectangle b: Wa*20=7*Wb*Hb
Replace Wa with 0.5Wb: 0.5Wb*20=7Wb*Hb => Hb=10/7
7 0
3 years ago
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