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3 years ago

Is 1/a rational or irrational

Mathematics

1 answer:

Firlakuza [10]3 years ago

5 0

Answer:

The number 1 can be classified as: a natural number, a whole number, a perfect square, a perfect cube, an integer. This is only possible because 1 is a RATIONAL number

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give the width of the lawnmower is 2.5 feet and the length of the rope is 25 feet, calculate the radius (R) of the pole that wil

3241004551 [841]

Answer:

The radius is 0.398 feet to produce a perfect lawn for the lawnmower.

It is given that the width of the lawnmower is 2.5 feet and the length of the rope is 25 feet.

It is required to calculate the radius (R) of the pole that will produce a perfect lawn.

What is a circle?

It is defined as the combination of points that and every point has an equal distance from a fixed point ( called the center of a circle).

We have,

Width of the lawnmower = 2.5 feet

Length of the rope = 25 feet

For the perfectly mowed lawn, it means the lawnmower width which is 2.5 feet must wrap the pole with radius R, mathematically:

The perimeter of the pole = width of the lawnmower

2πR = 2.5

R = 0.398 Feet ( π = 3.14 )

Thus, the radius is 0.398 feet to produce a perfect lawn for the lawnmower.

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3 years ago

A rectangular garden is fenced on all sides with 248 feet of fencing. The garden is 6 feet longer than it is wide. Fine the leng

Shalnov [3]

The total length of the fencing is 248 ft; we call this the "perimeter" of the garden. Since P = 2W + 2L in general, here:

P = 248 ft = 2W + 2(W+6), or 248 ft = 4W + 12.

Subtracting 12 from both sides of this equation: 236 ft = 4W. Then W = 59 ft, which means that L = 65 ft.

8 0

3 years ago

In the figure, ∆ABD ≅ ∆CBD by Angle-Side-Angle (ASA). Which segments are congruent by CPCTC?

Elis [28]

Answer: AB ≅ CB

Step-by-step explanation:

In the given figure, we have ∆ABD ≅ ∆CBD

The CPCTC property of congruent triangles says that if two triangles are congruent then their corresponding parts ( angles and segments ) are congruent.

Since we have given that ∆ABD ≅ ∆CBD.

Therefore, the corresponding segments are congruent.

As segment AB is corresponding to segment CB. [First two letters]

Therefore, segment AB is congruent to segment CB.

8 0

2 years ago

What is the value of arcsin(0) in degrees?<br><br> Enter your answer in the box.

melisa1 [442]

Answer:

Therefore,

The value of arcsin(0) is 0° or 180° or 360° or 540° or n×180° so on.

Step-by-step explanation:

To Find:

arcsin(0) in degrees =?

Solution:

' arcsin ' a mathematical function that is the inverse of the sine function.

Therefore, arcsin (x) is called the inverse sine function.

It is the angle whose sine is the number x.

So here we require angle in degree for which the Sine is '0'.

It is also written as

$\sin^{-1}x$

We Know that

$\sin 0\°=0\\or\\\sin 180\°=0$

Therefore,

$\arcsin (0) = 0\°\\or\\\arcsin (0) = 180\°$

Also integer multiples of 180° will have

$\arcsin (0)=n\times 180\°$

Where n = integer

Therefore for '0' we can have 2×180° , 3×180° , 4×180°....and so on i.e 360° , 540° and so on

Therefore,

The value of arcsin(0) is 0° or 180° or 360° or 540° or n×180° so on.

5 0

3 years ago

We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. (a) Find the probability th

Verizon [17]

Answer:

a) There is a 16.6% probability that doubles were rolled.

b) Given that the roll resulted in a sum of 6 or less, there is a 20% probability that doubles were rolled.

c) There is a 30.55% probability that at least one die is a 1.

Step-by-step explanation:

The probability formula is the number of desired outcomes divided by the number of total outcomes.

(a) Find the probability that doubles were rolled. (i.e. the two outcomes are equal)

There are six desired outcomes: (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)

There are 36 total outcomes. So:

$P = \frac{6}{36} = 0.166$

There is a 16.6% probability that doubles were rolled.

(b) Given that the roll resulted in a sum of 6 or less, find the conditional probability that doubles were rolled.

The following rolls result in a sum of 5 or less:

(1,1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (4,1), (4,2), (5,1)

So, there are 15 total outcomes.

3 of them are doubled: (1,1), (2,2), (3,3). So

$P = \frac{3}{15} = 0.2$

Given that the roll resulted in a sum of 6 or less, there is a 20% probability that doubles were rolled.

(c) Find the probability that at least one die is a 1

The following outcomes have at least one die that is 1:

(1,1), (1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(3,1),(4,1),(5,1),(6,1)

So, there are 11 desired outcomes out of 36.

$P = \frac{11}{36} = 0.3055$

There is a 30.55% probability that at least one die is a 1.

6 0

4 years ago