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LenaWriter [7]
3 years ago
8

What’s the answer???

Mathematics
1 answer:
enyata [817]3 years ago
5 0
Nikkis charges are 20,40,50,80. Dave’s charges are 25 and 37.5.
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Help me please its math
Reptile [31]
D=10
Explanations: 2d-5=3d- 15
2d- 3d =-15+5
D=10
6 0
2 years ago
Completely Factor 2n^2-23n+45=0
Anton [14]

Answer:

x=5/2, 9

Step-by-step explanation:

3 0
3 years ago
4x-2y=3<br> Solve for y<br> Please help right away!
baherus [9]
I do believe it is y=1/2+3
5 0
3 years ago
The lengths of lumber a machine cuts are normally distributed with a mean of 106 inches and a standard deviation of 0.3 inch. ​(
Vinvika [58]

Answer:

a) P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)

And we can find this probability with the complement rule:

P(z>0.37)=1-P(z

b) z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}=  2.431

And if we use the z score we got:

P(z>2.431) =1-P(z

Step-by-step explanation:

Let X the random variable that represent the lengths of a population, and for this case we know the distribution for X is given by:

X \sim N(106,0.3)  

Where \mu=106 and \sigma=0.3

Part a

We are interested on this probability

P(X>106.11)

And we can use the z score formula given by:

z=\frac{x-\mu}{\sigma}

And using this formula we got:

P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)

And we can find this probability with the complement rule:

P(z>0.37)=1-P(z

Part b

For this case we select a sample of n =44 and the new z score formula is given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score we got:

z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}=  2.431

And if we use the z score we got:

P(z>2.431) =1-P(z

6 0
2 years ago
(2.0 x 10-3) (3.5 x 10)<br> What is the value of the expression?
Mademuasel [1]

Answer:

595

Step-by-step explanation:

SOLUTION STEPS

(2.0×10−3)(3.5×10)

Multiply 2 and 10 to get 20.

(20−3)×3.5×10

Subtract 3 from 20 to get 17.

17×3.5×10

Multiply 17 and 3.5 to get 59.5.

59.5×10

Multiply 59.5 and 10 to get 595.

595

7 0
3 years ago
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