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koban [17]
3 years ago
11

It is well-known that monoalphabetic substitution cipher (also known as monoalphabetic cipher) is not secure, because it can be

subjected to frequency analysis.
a. True
b. False
Computers and Technology
1 answer:
olasank [31]3 years ago
5 0

Answer:

a. True

Explanation:

Encryption is a form of cryptography and typically involves the process of converting or encoding informations in plaintext into a code, known as a ciphertext. Once, an information or data has been encrypted it can only be accessed and deciphered by an authorized user.

Some examples of encryption algorithms are 3DES, AES, RC4, RC5, and RSA.

It is well-known that monoalphabetic substitution cipher (also known as monoalphabetic cipher) is not secure, because it can be subjected to frequency analysis.

The Playfair Cipher is generally considered to be the best multiple letter encryption cipher because it processes digrams in the plaintext as singular units and translates them directly into ciphertext digrams.

In the Playfair Cipher, a 5 × 5 matrix comprising of letters is developed using a keyword and then, the matrix is used to encrypt the plaintext as a pair i.e two letters at a time rather than as a single text.

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LargeCo is planning a new promotion in Alabama (AL) and wants to know about the largest purchases made by customers in that stat
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Answer:

Check the explanation

Explanation:

Assuming Cust_code is unique for every customer.

Query :

SELECT * FROM CUSTOMER WHERE CUST_STATE= "AL" GROUP BY CUST_CODE HAVING LARGEST INVOICE = MAX(LARGEST INVOICE) OR (LARGEST INVOICE =0 and INV_DATE IS NULL);

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3 years ago
About "How can computer help us in our life?​
Nitella [24]

Answer:

Explanation:

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3 years ago
Draw directed graphs representing relations of the following types.
mixas84 [53]

Answer:

The first graph in the picture describes a relation that is (a) Reflexive, transitive, and anti-symmetric.

Because a, b, c, d all are related to itself, so reflexive.

where (a, b) and (b, d) are in the relation, (a,d) is in the relation,    

for (c,a) and (a,b) there is (c,b).

so it's transitive.

for all a,b in the relation, (a,b) there is no (b,a) with a ≠b.

The second graph in the picture describes a relation that is (b) Reflexive, transitive, and neither symmetric nor anti-symmetric.

Because a, b, c, d all are related to itself, so reflexive.

where (a, b) and (b, a) are in the relation, (a,a) is in the relation,                                                    

where (c, d) and (d, d) are in the relation, (c,d) is in the relation,                                                    

so it's transitive.

Because, (a,b) and (b.a) are there, but for (c,d) there is no (d,c) in relation.

So, the relation is not symmetric.

(a,b) and (b,a) is in relation but, a≠b, so not anti symmetric.

Explanation:

For all a in a set,  if (a,a) in a relation then the relation is reflexive.

For all (a,b) in relation R, if (b,a) is also in R, then R is symmetric.

For all (a,b), (b,c) in relation R, if (a,c) is also in R, then R is transitive.

For all (a,b), (b,a) in R, a = b,  then R is an anti- symmetric relation.

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3 years ago
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