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scoundrel [369]
2 years ago
10

Create diagrams to represent the possible cases for common tangents between two circles. Explain why your diagrams satisfy the g

iven criteria.
One Common Tangent
a) Diagram: (I have this part its one circle inside of the other with one point of intersection if that makes sense)
b) Justification: (This is where I'm stuck)
Mathematics
1 answer:
Svetach [21]2 years ago
5 0
This is tooo hard. OH MY
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Factories A, B and C produce computers. Factory A produces 4 times as manycomputers as factory C, and factory B produces 7 times
Elina [12.6K]

Answer:

The  probability is   P(A') =  0.485

Step-by-step explanation:

Let assume that the number of computer produced by factory C is  k = 1  

 So  From the  question we are told that

       The number produced by  factory A is  4k =  4

        The  number produced by factory B is  7k  = 7

        The  probability of defective computers from A is  P(A) =  0.04

        The  probability of defective computers from B is  P(B)  =  0.02

        The  probability of defective computers from C is P(C) =  0.03

Now the probability of factory A producing a defective computer out of the 4 computers produced is  

       P(a) =  4 *  P(A)

substituting values

        P(a) =  4 * 0.04

        P(a) = 0.16

The probability of factory B producing a defective computer out of the 7 computers produced is  

       P(b) = 7  *  P(B)

substituting values

        P(b) =  7 * 0.02

        P(b) = 0.14

The probability of factory C producing a defective computer out of the 1 computer produced is  

       P(c) = 1  *  P(C)

substituting values

        P(c) =  1 * 0.03

        P(b) = 0.03

So the probability that the a computer produced from the three factory will be defective is  

     P(t) =  P(a) +  P(b) +  P(c)

substituting values

     P(t) =   0.16  + 0.14 +  0.03

     P(t) =   0.33

Now the probability that the defective computer is produced from factory A is

      P(A') =  \frac{P(a)}{P(t)}

       P(A') =  \frac{ 0.16}{0.33}

        P(A') =  0.485

3 0
3 years ago
There are 90 passengers on a commuter flight from SFO to LAX, of whom 27 are traveling on business. In a random sample of five p
stepladder [879]

Answer:

C). 0.83193

Step-by-step explanation:

There are total of 90 passengers of which 27 are for business.

The probability of passengers for business = 27/90

The probability of passengers for business p = 0.3

The probability of passengers not for business q = 1-The probability of passengers for business

= 1-0.3

= 0.7

Random sample of 5 passenger, probability of at least one business passenger = 1 - probability of no business passenger

probability of no business passenger

= 5C0(0.3)^0 * (0.7)^5

= 1 *1*0.16807

= 0.16807

probability of at least one business passenger = 1 - probability of no business passenger

= 1-0.16807

=0.83193

4 0
3 years ago
a plumber has a piece of pipe that is 2 meters long he needs to cut it into section of 10 centimeters long how many sections wil
ahrayia [7]
Since I can't post pictures in this answer, I will just tell you how to get the answer. For this question, you need to consider, how many centimeters go into 2 meters? Well, since 1 meter equals one hundred centimeters, 2 meters would equal 200 centimeters. And since we need to know how many 10 centimeter long sections there would be, then you need to divide 200 by 10. 200 divided by ten equals 20. So the answer would be 20 sections. The plumber is able to cut 20 sections. I hope that helped!
8 0
3 years ago
Read 2 more answers
Someone help with this math problem
7nadin3 [17]
She needs 1/6 almonds , 1/3 walnuts and 1/2 of raisins as a fraction of total trail mix.
So she spends $2.5 on almonds. $5 on walnuts and $10 on raisins (total $15)

so that is 2.5/12 =  0.208  pounds almonds
5 / 10.5 =  0.476 pound walnuts
10/4 =  2.5 pounds raisins

so total wieght of the trail mix is 3.19 pounds

8 0
3 years ago
lemon looked at 26 Web sites in 39 minutes. at that rate, how many Web sites would she look at in 12 minutes?
nignag [31]

8 websites in 12 minutes


Hope this helped :)

6 0
3 years ago
Read 2 more answers
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