<u>Explanation</u><u>:</u>
Consider ABCD is a rhombus
We know that
All sides are equal in rhombus i.e,
⇛AB=BC=CD=DA
and AC and BD are digonals
Given that
Diagonal and the side of the rhombus are equal.
⇛AB = BC = CD = DA = AC
Diagonal AC divides the rhombus into two triangles .
They are ∆ BAC and ∆ DAC
In triangle BAC
BA=BC=AC,(Given)
⇛∠ BAC=∠ABC= ∠ACB =60°→→→Eqn(i)
Similarly in ∆DAC ,
DA=DC=AC
⇛∠DAC=∠ACD=∠ADC=60°→→→Eqn(ii)
From eqn(i) and eqn(ii)
∠A=∠BAC+∠DAC=60°+60°=120°
and
∠B= ∠ABC = 60°.
and
∠C=∠ACB+∠ACD=60°+60°=120°
and
∠D =∠ADC=60°
∴ ∠A = 120° , ∠B = 60° ,∠C = 120° & ∠D = 60°
<u>Answer:</u><u>-</u>The measures of the all angles in the rhombus are 120° , 60° ,120° and 60°.
Note: [Figure refers in the attached file.
I think is 1863 m because if you use the formula for area
It will be 5 out of 9 times you will pull a red marble
Answer:
y=4x
Step-by-step explanation:
Answer: 
Step-by-step explanation:
Given : An equation relating packets to bytes of information : 
where<em> p</em> represents the number of packets and <em>b</em> represents the number of bytes of information.
1 byte = 8 bits
Let x= Number of bits such that 1 b = 8x
Put b = 8x in given equation , we get
Divide both sides by 8 , we get
Hence, the equation represent the relationship between the number of packets and the number of bits :
