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frozen [14]
3 years ago
13

Whats 1 and 2/3 + 1 and 5/6​

Mathematics
2 answers:
Dima020 [189]3 years ago
7 0
1 2/3 + 1 5/6

We’ll start by converting the 2/3 to 6ths so we have a common denominator.

Look at the denominator first. 3 x 2 is 6, so we need to multiply the numerator by 2 as well. 2/3 = 4/6.

So we have 1 4/6 + 1 5/6 = 2 9/6
But you know they’ll want you to reduce that so it’s 3 3/6...or 3 1/2.

Let me know where you have questions.
serious [3.7K]3 years ago
4 0

Answer:

3 1/2

Step-by-step explanation:

( 1 + 1 ) ( 2/3 + 5/6 )

2 + 3/2

2 + 1 1/2

= 3 1/2

Hope this helps dude

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An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 75 type K batteries and a sample of 46
lorasvet [3.4K]

The decision rule for rejecting the null hypothesis, considering the t-distribution, is of:

  • |t| < 1.9801 -> do not reject the null hypothesis.
  • |t| > 1.9801 -> reject the null hypothesis.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is not enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means is of zero, hence:

H_0: \mu_1 - \mu_2 = 0

At the alternative hypothesis, it is tested if there is enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means different of zero, hence:

H_1: \mu_1 - \mu_2 \neq 0

We have a two-tailed test, as we are testing if the mean is different of a value.

Considering the significance level of 0.05, with 75 + 46 - 2 = 119 df, the critical value for the test is given as follows:

|t| = 1.9801.

Hence the decision rule is:

  • |t| < 1.9801 -> do not reject the null hypothesis.
  • |t| > 1.9801 -> reject the null hypothesis.

More can be learned about the t-distribution in the test of an hypothesis at brainly.com/question/13873630

#SPJ1

3 0
1 year ago
Which quadratic function is represented by the table ???
Ulleksa [173]

Answer:

B) f(x) = 3x² - 2x + 5

Step-by-step explanation:

To find the correct quadratic function that represents the table, you must substitute [x] into the quadratic function.

A) f(x) = 3x² + 2x - 5

B) f(x) = 3x² - 2x + 5

C) f(x) = 2x² + 3x - 5

D) f(x) = 2x² - 2x + 5

A.   3(-2)² + 2(-2) - 5 =

3(4) - 4 - 5

12 -  4 - 5

12 - 9

= 3

B.   3(-2)² - 2(-2) + 5 =

3(4) + 4 + 5

12 + 9

= 21

C.   2(-2)² + 3(-2) -5 =

2(4) - 6 - 5

8 - 11

= - 3

D.   2(-2)² + 2(-2) + 5 =

2(4) - 4 + 5

8 - 4 + 5

8 + 1

= 9

Your correct answer is: B

8 0
3 years ago
jane can do a job in 3 hours, while gary can do the same job in 2 hours. if jane works alone for an hour before gary helps her h
Rudiy27

Answer: 2hrs?

Step-by-step explanation: 3-2=1+1 hour she took alone = 2hrs

8 0
2 years ago
Read 2 more answers
Find the value of x in the equation √ x + 5 = √ x + 45.
Ivanshal [37]
There is no solution since 5 doesn't equal 45
8 0
3 years ago
Please help me <br> Show your work <br> 10 points
Svet_ta [14]
<h2>Answer</h2>

After the dilation \frac{5}{3} around the center of dilation (2, -2), our triangle will have coordinates:

R'=(2,3)

S'=(2,-2)

T'=(-3,-2)

<h2>Explanation</h2>

First, we are going to translate the center of dilation to the origin. Since the center of dilation is (2, -2) we need to move two units to the left (-2) and two units up (2) to get to the origin. Therefore, our first partial rule will be:

(x,y)→(x-2, y+2)

Next, we are going to perform our dilation, so we are going to multiply our resulting point by the dilation factor \frac{5}{3}. Therefore our second partial rule will be:

(x,y)→\frac{5}{3} (x-2,y+2)

(x,y)→(\frac{5}{3} x-\frac{10}{3} ,\frac{5}{3} y+\frac{10}{3} )

Now, the only thing left to create our actual rule is going back from the origin to the original center of dilation, so we need to move two units to the right (2) and two units down (-2)

(x,y)→(\frac{5}{3} x-\frac{10}{3}+2,\frac{5}{3} y+\frac{10}{3}-2)

(x,y)→(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

Now that we have our rule, we just need to apply it to each point of our triangle to perform the required dilation:

R=(2,1)

R'=(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

R'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(1)+ \frac{4}{3})

R'=(\frac{10}{3} -\frac{4}{3} ,\frac{5}{3}+ \frac{4}{3})

R'=(2,3)

S=(2,-2)

S'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

S'=(\frac{10}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

S'=(2,-2)

T=(-1,-2)

T'=(\frac{5}{3} (-1)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

T'=(-\frac{5}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

T'=(-3,-2)

Now we can finally draw our triangle:

8 0
3 years ago
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