A population of frogs consists of 81 percent with speckles (recessive) and 19 % without speckles (dominant). What are the freque
ncies of p and q alleles if this population is in Hardy-Weinberg equilibrium? Show work.
1 answer:
The correct answer would be the frequency of the recessive allele in a population
The Hardy-Weinberg equations are
p + q = 1
p² + q² + 2pq = 1
p stands for the frequency of a dominant allele in a population.
q stands for the frequency of a recessive allele in a population.
You might be interested in
Egg cel :) because egg cells are used to produce offspring.
Answer:
base pairs....................
Answer:
No, the population is not in Hardy-Weinberg Equilibrium because the frequencies of alleles have changed over the four generations.
Explanation:
sacrificed a wrong answer for this ( u _ u; )
Answer chooses will help .
Explain what you mean and I can try and help