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Ahat [919]
3 years ago
7

Given that AB:BC is 4:3 and AC = 56. Find AB. A B

Mathematics
1 answer:
Phantasy [73]3 years ago
3 0

Answer:

ab=32

Step-by-step explanation:

ab:bc

4:3

abc= 56

4+3=7

56÷7=8

ab= 8x4=32

bc=8x3=24 #

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How many 5 cents can u get from $1.25?​
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25

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3 years ago
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Miya went to the bowling alley. There was a $5 shoe rental fee plus $15.0 per game. Which equation models the situation where g
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7 0
2 years ago
Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2
Vsevolod [243]

Answer:

Given that:

a = (\frac{x+ip}{2})^{\frac{1}{2}} and a+= (\frac{x-ip}{2})^{\frac{1}{2}}

if a , a+ commutator, it obeys aa^+ = a^+a

First find:

aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}

                = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

Now;

a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}

              =(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

therefore, aa^+ = a^+a which implies the operators a and a+ are commutators.    


7 0
3 years ago
9 to the power 3 + 3 to the power 2 + 6 to the power 3 + 15 power 2 equals to how much
Llana [10]
Hey! So, here's a tip. When writing exponents, an easier way is to write a^b, rather than a to the b power. Besides that, here is your answer!


So-------

9^3=729

3^2=9

6^3=216

15^2=225



Now that we have that figured out, we can add them together, wish is simple. 729 + 9 + 216 + 225= 1,179.



Therefore, your final answer will be 1,174.




If you have any questions on this, I'm happy to help you. :)




3 0
3 years ago
Read 2 more answers
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