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kumpel [21]
2 years ago
13

Determine the value of x in each triangle

Mathematics
1 answer:
tensa zangetsu [6.8K]2 years ago
8 0

Answer:

180

Step-by-step explanation:

Subtract the sum of the two angles from 180 degrees.

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Solve |x−4|+3=3.Then explain your result that you discovered. How many solutions did you get and why?
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2 years ago
Show me the equation that represents a slope with a nine over five in a Y intercept of six
mixer [17]
Y = (9/5)x + 6

Explanation: given the info given we can plug in the numbers into the linear equation:
y= mx + b
Where m is the slope and b is the y-intercept
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1 year ago
Researchers are interested in the effect of a certain nutrient on the growth rate of plant seeding. Use a hydroponics grow proce
Rashid [163]

Answer:

The 95% confidence interval for the mean would be given by (56.604;68.596)

The 99% confidence interval for the mean would be given by (53.196;72.004)

Step-by-step explanation:

1) Previous concepts

When we compute a confidence interval for the mean, we are interested on the parameter population mean, and we use the info from the sample to estimate this parameter.

2) Basic operations

The sample mean can be calculated with the following formula

\sum_{i=1}^n \frac{x_i}{n}

Using excel we can use this function to calculate the mean:

=AVERAGE(54.2,59.8,61.8,63.3,65.1,71.4)

The value obtained is \bar X=62.6

In order to find the sample deviation we can use this formula

s=\sqrt{\sum_{i=1}^n \frac{(x_i-\bar X)^2}{n-1}}

And using excel we can use this function to calculate the sample standard deviation:

=STDEV.S(54.2,59.8,61.8,63.3,65.1,71.4)

The value obtained is s=5.713

The sample size for this case is n=6, n<30 so then is better use the t distribution to calculate the margin of error. First we need to calculate the degrees of freedom, on this case df=n-1=6-1=5

The formula for the confidence interval would be given by:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

3) Part a

If we want a 95% or 0.95 of confidence, then the value for the signficance is \alpha=1-0.95=0.05, and \alpha/2=0.025, and 1-\frac{\alpha}{2}=0.975 so we can find the critical t value with the following formula in excel:

=T.INV(0.975,5)

And we got t_{\alpha/2}= 2.571

And we can replace into equation (1) and we got:

62.6 \pm 2.571\frac{5.713}{\sqrt{6}}

And using excel with the following formulas we got:

=62.6-2.571*(5.713/SQRT(6)) = 56.604

=62.6+2.571*(5.713/SQRT(6)) = 68.596

So the 95% confidence interval for the mean would be given by (56.604;68.596)

4) Part b

If we want a 99% or 0.99 of confidence, then the value for the signficance is \alpha=1-0.99=0.01, and \alpha/2=0.005, and 1-\frac{\alpha}{2}=0.995 so we can find the critical t value with the following formula in excel:

=T.INV(0.995,5)

And we got t_{\alpha/2}= 4.032

And we can replace into equation (1) and we got:

62.6 \pm 4.032\frac{5.713}{\sqrt{6}}

And using excel with the following formulas we got:

=62.6-4.032*(5.713/SQRT(6)) = 53.196

=62.6+4.032*(5.713/SQRT(6)) = 72.004

So the 99% confidence interval for the mean would be given by (53.196;72.004)

8 0
3 years ago
Question is down below ​
algol [13]

Answer:

The 3rd quartile

Step-by-step explanation:

The median to referred to as the 2nd quartile which is in the middle. To the right of the median is the 3rd quartile. Hope this helps! :)

7 0
3 years ago
Read 2 more answers
The point A(-2, 3) is translated using T: (x,y) = (x + 4, y + 2).
Charra [1.4K]

Answer: Choice D) 2\sqrt{5}

===========================================================

Work Shown:

Point A starts at (-2,3) and moves to (2,5) after applying the translation rule of "shift 4 to the right, 2 up".

Use the distance formula to find the distance from (-2,3) to (2,5)

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-2-2)^2 + (3-5)^2}\\\\d = \sqrt{(-4)^2 + (-2)^2}\\\\d = \sqrt{16 + 4}\\\\d = \sqrt{20}\\\\d = \sqrt{4*5}\\\\d = \sqrt{4}*\sqrt{5}\\\\d = 2\sqrt{5}\\\\d \approx 4.472136\\\\

6 0
3 years ago
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