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3 years ago

What is a circumference

Mathematics

1 answer:

cluponka [151]3 years ago

7 0

Answer:

25.13

Step-by-step explanation:

2 pie multiply radius

2 pie multiply 4

( I think so)

I hope this helps

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An airplane travels at a speed of 960 km/h how for can it travel in 1 hour

Marat540 [252]

Answer:

960 km

Step-by-step explanation:

Speed = Distance/Time.

From the question, we are to find the Distance.

The formula for Distance is given as:

Speed × Time.

From the question:

Speed = 960 km/hr

Time = 1 hour

Distance = 960 km/hr × 1 hour

Distance = 960 km

Therefore, the airplane can travel for 960km in 1 hour

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3 years ago

In the past you paid $800$800 per month to rent your apartment. You now pay $900$900 per month for your rent. What is the percen

Gnesinka [82]

The persent increase is 200%

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4 years ago

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The volume of this rectangular prism is 1,260 cubic meters. What is the value of m?

guajiro [1.7K]

Answer:

The value of M would be 18

Step-by-step explanation:

It's 18 because if we do 5 x 14 x 18 it would give us 1,260 cm

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3 years ago

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Answer the question :)

inn [45]

Answer:

A. -11

Step-by-step explanation:

In the function, replace x with -2

R(x) = x^2 - 3x - 1 ➡ R(-2) = (-2)^2 - 3 × 2 -1 = -11

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4 years ago

Finding an Equation of a tangent Line in Exercise, find an equation of the tangent line to the graph of the function at the give

frutty [35]

Answer:

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

$g(x) =e^{x^3}$

we know that $\frac{d}{dx}(e^{f(x)})=e^{f(x)}f'(x)$

$g'(x) =e^{x^{3}}(3 x^{2})$

$g'(x) =3 x^{2} e^{x^{3}}$

this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

$m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}$

using the equation of line:

$(y-y_1)=m(x-x_1)$

we'll find the equation of the tangent line.

here (x1,y1) =(-1,1/e), and m = 3/e

$(y-\dfrac{1}{e})=\dfrac{3}{e}(x+1)\\y=\dfrac{3x}{e}+\dfrac{3}{e}+\dfrac{1}{e}\\$

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

3 0

3 years ago

What is a circumference ​

What is a circumference