Ask question

Ask question

All categories

2 years ago

6

Kpop and bts is trash dont try getting mad at me

2 answers:

sp2606 [1]2 years ago

6 0

Answer:

you are correct

Step-by-step explanation:

They are really bad please do not like bts

musickatia [10]2 years ago

3 0

Answer:

Do you really have to go out of your way to say something like this?

I respect your opinion on not liking them but to hate on them and tell people not to stan them is a bit harsh. They are pretty talented and worked really hard and put there own efforts to get to where they are today. There music may not fit your music taste and that is totally fine. I hope you understand

You might be interested in

Look at the picture of a scaffold used to support construction workers. The height of the scaffold can be changed by adjusting t

Arturiano [62]

Answer:

You didn't give us a picture to look at

Step-by-step explanation:

7 0

2 years ago

F(x)=bx^2+32 For the function f defined above, b is a constant and f(2)=40. What is the value of f(-2)?

zhuklara [117]

Answer:

f(-2) = 0

Step-by-step explanation:

Given that:

f(x) = bx^2 + 32

f(2) = b(2)^2 + 32

f(2) = 4b + 32

f(2) = 4b = -32

f(2) = b = -32/4

f(2) = b = -8

Thus;

f(-2) = -8(-2)^2 + 32

f(-2) = -8(4) + 32

f(-2) = -32 + 32

f(-2) = 0

6 0

2 years ago

Read 2 more answers

If a chicken lays 16 eggs every 40 days, what is the average number of eggs she lays per day?

Basile [38]

Answer:

40 / 16 = 2.5

Step-by-step explanation: ur telling me this is highschool math? lol. im in middle school but took this stuff in third grade.

5 0

2 years ago

Read 2 more answers

Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

2 years ago

Write a linear function f with the given values.<br><br> f(x) =

Allushta [10]

Answer:

f(x) = -2x + 1

Step-by-step explanation:

8 0

2 years ago