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kicyunya [14]
3 years ago
15

Someone help and plz make sure it’s right

Mathematics
1 answer:
Paha777 [63]3 years ago
3 0
The answer for this would be 10
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Can someone help me. ​
marshall27 [118]

Answer:

B

Step-by-step explanation:

yeah just pick B man lol

7 0
3 years ago
(I will give brainliest. Please answer quickly)
ladessa [460]

The first step to solve this problem is to find the area of the rectangular piece of fabric.

A of triangle = bh/2

A = (14 cm) (6 cm) /2

A = 84 cm^2 / 2

A = 42 cm

And since there are 31 pieces of the fabric, the total area of all the pieces of fabric is:

31 pieces of fabric x 42 square centimeters per piece = 1,302 square centimeters

To computer how many congruent triangular patches can be cut, you have to divide the total area of the fabric pieces with the area of the congruent triangle:

1,302 square centimeters / 21 square centimeters = 62

Therefore, Leia can cut 62 patches.

4 0
3 years ago
Please help on the Line Plot one! ASAP! Please
tamaranim1 [39]
Draw a straight, horizontal line.  Mark evenly-spaced scale divisions, 0 to 5 (because all of the given numerals fit within this domain).

Recognize that the LCD of these fractions and mixed numbers is 6.

Convert all of the given fractions to denominator 6, as needed (some already have that denominator).

Arrange the resulting fractions in ascending order.  For example, 5/6, 1/6, 3/6 would become 1/6, 3/6, 5/6 (in ascending order).

Plot all your numerals (all of which have denominator 6) on your number line.
6 0
3 years ago
A circle had a sector with area 33pi and central angle of 11/6pi radians
MissTica

Answer:

The area of the circle is 36\pi\ units^{2}

Step-by-step explanation:

we know that

The area of a circle subtends a central angle of 2\pi radians

so

By proportion find the area of the circle

\frac{33\pi }{(11\pi /6)}=\frac{x}{2\pi}\\ \\ x=2\pi*( 33*6)/11\\ \\x=36\pi\ units^{2}

3 0
4 years ago
Read 2 more answers
Please help with 3 questions and show all work!!!
sergeinik [125]
Question 1:
Since the triangles are congruent, we know that QS = TV
This means that 
3v + 2 = 7v - 6
Subtract both sides by 2
3v = 7v - 8
Subtract 7v from both sides
-4v = -8
Divide both sides by -4
v = 2
Plug this value back into 3v + 2 and you get 8.
QS = 8
Since the triangles are congruent
QS = 8    AND    TV = 8

Question 2:
So we know that AC = AC because that's a shared side.
It's also given that BC = CD.
In order for two triangles to be congruent by SAS, the angle between the two sides must be congruent.
That means angle C must be congruent to angle C from the other triangle.

Question 3:
We know that AC = AC because it's a shared side.
We also know that angle A from one triangle is equal to angle C from the other.
However, for a triangle to be congruent by SAS, the congruent angle must be between two congruent sides. 
In order for us to prove congruence by SAS, AD must be congruent to BC.

Have an awesome day! :)
3 0
3 years ago
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