Answer:
True
Step-by-step explanation:
We can plug in and see.
If (3,0) is on the graph of P, then P(3) will evaluate to 0.
Let's try it:
P(3)=(3)^3-7(3)^2+15(3)-9
P(3)=27-7(9)+45-9
P(3)=27-63+45-9
P(3)=-36+45-9
P(3)=9-9
P(3)=0
Since P(3)=0, then (3,0) is an ordered pair of P.
I agree with the answer above
4k-6=-2k-16-2
4k-6=-2k-18
6k-6=-18
6k=-12
k=-2
Answer:
hold my picolr
Step-by-step explanation:
