Both base and height of the sail is 40 1/2 feet.
A sail is triangular in shape. Finding the area of a triangle is multiplying its base and height and dividing the product by 2.
A = 1/2 bh
Area = 40 1/2 or 40.50 sq. ft
Since base and height are equal.
40.50 x 2 = 81
bh = 81
bh = 81 ÷ 2
b = 40 1/2 ft
h = 40 1/2 ft
Answer:
The answer for the value of x is, x=20
It's a little hard to see, but I'm almost positive the y intercept is -1.
Remember, the y intercept is wherever the line intercepts in the y axis 0.
Good luck my man.
W=-5 because you distribute at the beginning with the 2 variables and you solve that's equation and you will end up with 6w divided by 30 and that's will give u W=-5
Answer:
<u>height</u><u>,</u><u> </u><u>x</u><u> </u><u>is</u><u> </u><u>2</u><u>3</u><u>5</u><u> </u><u>ft</u>
Step-by-step explanation:
From trigonometric ratios:
![\cos( \theta) = \frac{adjacent}{hypotenuse}](https://tex.z-dn.net/?f=%20%5Ccos%28%20%5Ctheta%29%20%20%3D%20%20%5Cfrac%7Badjacent%7D%7Bhypotenuse%7D%20)
but:
![\theta = 90 \degree - 36 \degree \\ \theta = 54 \degree](https://tex.z-dn.net/?f=%20%5Ctheta%20%3D%2090%20%5Cdegree%20-%2036%20%5Cdegree%20%5C%5C%20%20%5Ctheta%20%3D%2054%20%5Cdegree)
adjacent is x
hypotenuse is 400 ft
![\ \cos ( 54 \degree) = \frac{x}{400} \\ \\ x = 400 \ \cos (54 \degree) \\ x = 235 \: \: feet](https://tex.z-dn.net/?f=%20%5C%20%5Ccos%20%28%2054%20%5Cdegree%29%20%20%3D%20%20%5Cfrac%7Bx%7D%7B400%7D%20%20%5C%5C%20%20%5C%5C%20x%20%3D%20400%20%5C%20%5Ccos%20%2854%20%5Cdegree%29%20%20%5C%5C%20x%20%3D%20235%20%5C%3A%20%5C%3A%20%20feet)