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Tcecarenko [31]
3 years ago
14

Pete is standing 2 feet away from a mirror on the ground. Pete is 4 feet tall and can just see the top of the tree in the mirror

from where he is standing. The two triangles formed in the picture above are similar.
If the mirror is 10 feet away from the base of the tree, how tall is the tree?
A.5 feet
B.20 feet
C.12 feet
D.13 feet
Mathematics
2 answers:
Andre45 [30]3 years ago
5 0
I’m pretty sure the answer is D
puteri [66]3 years ago
4 0

Answer:

13 feet

Step-by-step explanation:

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To solve this problem simplify 9/2 widgets to 4.5. Next, multiply that number by 6. (1/6*6=I full hour). 

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William is going to invest in an account paying an interest rate of 5.9% compounded
Valentin [98]

Answer:

\$400.92  

Step-by-step explanation:

we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

t=19\ years\\ A=\$1,230\\ r=5.9\%=5.9/100=0.059  

substitute in the formula above

1,230=P(e)^{0.059*19}  

solve for P

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3 0
4 years ago
The length of a rectangle is seven more than double the width. If the perimeter is 22 inches find the dimensions
lubasha [3.4K]

Answer:

width = 1 1/3 inches

length = 9 2/3 inches

Step-by-step explanation:

let 'w' = width

let '7+2w' = length

P = 2l + 2w

22 = 2w + 2(7+2w)

22 = 2w + 14 + 4w

8 = 6w

w = 4/3 or 1 1/3

substitute 1 1/3, or 4/3, to find length:

l = 7 + 2(4/3)

l = 7 + 8/3 or 9 2/3

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3 years ago
Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t
dmitriy555 [2]

Answer:

1. Find the difference between the areas.

<u>Area of the small rectangle</u>: (x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14

<u>Area of the big rectangle</u>: (x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99

The difference is: 11x+85

( x^2+20x+99)- (x^2+9x+14)=x^2+20x+99-x^2-9x-14=11x+85

2.

You can solve this question just by looking at the graph.

a) The height is 4 meters.

f(d)=h=-2d^2+7d+4

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

f(0)=h=-2(0)^2+7(0)+4

h=4

The height is 4 meters.

b) 9 meters.

For d=1

f(1)=h=-2(1)^2+7(1)+4

f(1)=h=-2+7+4

h=9

b) The ball travels 4 meters.

But to calculate it, it is when h=0

0=-2d^2+7d+4

Using the quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$

$d=\frac{-7\pm\sqrt{81}}{-4}$

$d=\frac{-7\pm9}{-4}$

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

3.

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

The volume of a cylinder:

V=\pi r^2h

V=\pi (2.5)^2 \cdot 5

V=31.25 \pi

V_{c} \approx 98.17 \text{ m}^3

The volume of the sphere:

$V=\frac{4}{3}  \pi r^2$

V_{s} \approx 65.4 \text{ m}^3

The volume of the capsule is approximately 163.57  \text{ m}^3

3 0
4 years ago
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