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kondor19780726 [428]
2 years ago
6

Use natural logarithms to solve the equation. Round to the nearest thousandth.

Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
6 0

Answer:

x=\frac{ln(\frac{19}{7}) }{2}

Step-by-step explanation:

7*e^2x + 10 = 29

Subtract 10 to both side.

7*e^2x = 19

Divide 7 to both side.

e^2x = 19/7

Inverse e with ln.

ln(19/7) = 2x

Divide 2 to both side.

x=\frac{ln(\frac{19}{7}) }{2}

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Answer:

thats multiplication

Step-by-step explanation:

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3 years ago
The following is an incomplete paragraph proving that the opposite sides of parallelogram ABCD are congruent:
Semmy [17]

Answer:  Triangles BCA and DAC are congruent according to the Angle-Side-Angle (ASA) Theorem.

Step-by-step explanation:

Given : ABCD is a parallelogram.

That is, AB ║ CD and AD ║BC

We have to prove that: AB≅CD and AD≅BC

Proof:

Construct diagonal AC in the parallelogram ABCD.

Since, AC ≅ AC ( reflexive)

∠ BAC ≅ ∠ DCA  ( By the alternative interior angle theorem)

∠ BCA ≅ ∠ DAC   ( By the alternative interior angle theorem)

⇒ Δ BCA ≅ Δ DAC ( By ASA congruence postulate )

⇒ AB≅CD as well as AD≅BC ( BY CPCTC )

Thus, the opposite side of the parallelogram are congruent.



4 0
4 years ago
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Step-by-step explanation:

7 0
3 years ago
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Given that 3^x = 4^y = 12^z, show that z = (xy)/(x+y).
irinina [24]
3^{x} = 4^{y} = 12^{z}
3^{x} = 4^{y} = (4 \cdot 3)^{z}
3^{x} = 4^{y} = 4^{z} \cdot 3^{z}

\text{Let a } = 3^{x} = 4^{y} = 4^{z} \cdot 3^{z}
log_3a = x
log_4a = y
log_{(4 \cdot 3)}a = z

Using change of base:
x = \frac{lna}{ln3}
y = \frac{lna}{ln4}
z = \frac{lna}{ln(4 \cdot 3)}

ln3 = \frac{lna}{x}
ln4 = \frac{lna}{y}
ln(4 \cdot 3) = \frac{lna}{z}

Now, ln(4 · 3) = ln(4) + ln(3)

\frac{lna}{z} = \frac{lna}{x} + \frac{lna}{y}
\frac{1}{z} = \frac{1}{x} + \frac{1}{y}
\frac{1}{z} = \frac{x + y}{xy}

\therefore z = \frac{xy}{x + y}
8 0
4 years ago
Find the new cost including Sales Tax:<br> $99 headphones; 5% tax
rjkz [21]

Answer:

103.95

Step-by-step explanation:

99×5/100=4.95

99+4.95=103.95

6 0
3 years ago
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