Answer:
(b) {-8, 2}
Step-by-step explanation:
The given equation
x³ +6x -16 = 0
cannot be factored in integers. It has one irrational real root near x=1.759, and two complex roots.
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Perhaps you want to factor ...
x² +6x -16 = 0
(x +8)(x -2) = 0
This has solutions x = -8 and x = 2 that make the factors be zero.
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<em>Additional comment</em>
"Cubed" refers to an exponent of 3.
Answer:
see explanation
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
here (h, k) = (- 3, - 14), thus
y = a(x + 3)² - 14
To find a substitute (0, - 13) into the equation
- 13 = 9a - 14 ( add 14 to both sides )
9a = 1 ( divide both sides by 9 )
a = , hence
y = (x + 3)² - 14 ← equation of parabola
To find the x- intercepts let y = 0
(x + 3)² - 14 = 0
Multiply through by 9
(x + 3)² - 126 = 0 ( add 126 to both sides )
(x + 3)² = 126 ( take the square root of both sides )
x + 3 = ± = ± 3
Subtract 3 from both sides
x = - 3 ± 3
The x- intercepts are therefore
x = - 3 - 3 ≈ - 14.22 ( to 2 dec. places ) or
x = - 3 + 3 ≈ 8.22 ( to 2 dec. places )
