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2 years ago

Please help me with the correct answer

Mathematics

1 answer:

Shkiper50 [21]2 years ago

8 0

Answer:

Step-by-step explanation:

c² = a² + b²

= 8² + 6²

= 64 + 36

= 100

c² = 100

c = 10

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Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x

Lynna [10]

ANSWER

1.39

EXPLANATION

The given quadratic equation is

$0 = 2 {x}^{2} + 3x - 8$

This is the same as,

$2 {x}^{2} + 3x - 8 = 0$

Comparing to

$a {x}^{2} + bx + c = 0$

We have

a=2, b=3,c=-8

Using the quadratic formula, the solution is given by:

$x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a}$

We substitute the values to get,

$x = \frac{ - 3\pm \: \sqrt{ {3}^{2} - 4(2)( - 8)} }{2(2)}$

$x = \frac{ - 3\pm \: \sqrt{ 73} }{4}$

The positive root is

$x = \frac{ - 3 + \: \sqrt{ 73} }{4} = 1.39$

to the nearest hundredth.

4 0

3 years ago

Read 2 more answers

How to show these 2 problems are inverses

nataly862011 [7]

$\bf \begin{cases}
f(x)=\sqrt[3]{7x-2}\\\\
g(x)=\cfrac{x^3+2}{7}
\end{cases}\\\\
-----------------------------\\\\
now
\\\\
f[\ g(x)\ ]\implies f\left[ \frac{x^3+2}{7} \right]\implies \sqrt[3]{7\left[ \frac{x^3+2}{7} \right]-2}\implies \sqrt[3]{x^3+2-2}
\\\\\\
\sqrt[3]{x^3}\implies x\\\\
-----------------------------\\\\
or
\\\\
g[\ f(x)\ ]\implies g\left[\sqrt[3]{7x-2}\right]\implies \cfrac{\left[\sqrt[3]{7x-2}\right]^3+2}{7}
\\\\\\
\cfrac{7x-2+2}{7}\implies \cfrac{7x}{7}\implies x$

thus f[ g(x) ] = x indeed, or g[ f(x) ] =x, thus they're indeed inverse of each other

8 0

3 years ago

Please help me with 6-9!!

kolezko [41]

I got C for 6 & 7. I haven't done this in a while so I don't know 8 & 9. I hope I helped!

4 0

3 years ago

Renna pushes the elevator button, but the elevator does not move. The mass limit for the elevator is 450 kilograms (kg), but Ren

liraira [26]

The picture below has both of the answers to your problem.

7 0

3 years ago

Read 2 more answers

Solve by Elimination<br> b) -4x+2y=-4<br> 4x-5y=-8

ruslelena [56]

Answer:

x = 3

y = 4

Step-by-step explanation:

-4x+2y=-4 -----(eq1)

4x-5y=-8 ------(eq 2)

by elimination,

(eq1) + (eq 2),

(-4x+2y) + (4x-5y) = -4 + (-8)

-4x+2y + 4x-5y = -4 -8

2y-5y = -12

-3y = -12 (divide both sides by -3)

y = -12 / (-3) = 12/3 = 4 (sub back into (eq 1) )

-4x+2y=-4 -----(eq1), when y = 4,

-4x+2(4)=-4

-4x+8 = -4 (subtract 8 from both sides)

-4x= -4 - 8

-4x= -12 (divide both sides by -4)

x = -12 / (-4) = 3

5 0

3 years ago