The classifications of the functions are
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
<h3>How to classify each function accordingly?</h3>
The categories of the functions are given as
- A vertical stretch
- A vertical compression
- A horizontal stretch
- A horizontal compression
The general rules of the above definitions are:
- A vertical stretch --- g(x) = a f(x) if |a| > 1
- A vertical compression --- g(x) = a f(x) if 0 < |a| < 1
- A horizontal stretch --- g(x) = f(bx) if 0 < |b| < 1
- A horizontal compression --- g(x) = f(bx) if |b| > 1
Using the above rules and highlights, we have the classifications of the functions to be
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
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Answer:
B. 8.
D. log2 256.
Step-by-step explanation:
Generally:
loga b + loga b
= loga b^2.
Therefore log2 16 + log2 16
= log2 16^2
= log2 256.
From the above:
256 = 2^x where x is the log.
Now 2^8 = 256 so the original log2 16 + log2 16 = 8.
Answer:
You take 13x25x11 or as i like to do it take the lowest numbers and multiply them first like this so take 13x11=143 then times that by 25! 143x25=3575!
Step-by-step explanation:
You take all the numbers and multiply them like said in the answer!
Hope This Helped!
Answer:
The answer is > (greater than)
Step-by-step explanation:
It is > because if MN is the larger side and the largest angle would be across from the largest side, then that would make the largest angle, angle 2 and that would in turn make 3 the smaller angle. I know this is correct because I got it right.
