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Kaylis [27]
3 years ago
5

Find the value of x in the trapezoid below. Show equations and all work that leads to your answer.

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
8 0

Since the side is a transversal to the parallel bases, the angles formed are supplementary. This lets you write the relation

... (3x-5)° + (5x+13)° = 180°

... 8x +8 = 180

... x = (180 -8)/8 = 21.5

The value of x is 21.5.

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Find the Unit Rate in decimal representation. Round to the nearest hundredth, if
Mekhanik [1.2K]

Answer:

$4.1

Step-by-step explanation:

To find the Unit Rate, you have to find how much it cost of 1 lb. So, you have to divide 16 and 3.99

16/3.99

= 4.01002506

≈ $4.1

6 0
2 years ago
Does the point(1, 8)satisfy the inequality y ≥ 6x + 2 ?
nalin [4]

Answer: Yes

Step-by-step explanation:

1. Substitute 1 for x

2. 6 times 1 is 6 plus 2 is 8

3.8 is equal to or greater than 8

4 0
3 years ago
Sketch the domain D bounded by y = x^2, y = (1/2)x^2, and y=6x. Use a change of variables with the map x = uv, y = u^2 (for u ?
cluponka [151]

Under the given transformation, the Jacobian and its determinant are

\begin{cases}x=uv\\y=u^2\end{cases}\implies J=\begin{bmatrix}v&u\\2u&0\end{bmatrix}\implies|\det J|=2u^2

so that

\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\iint_{D'}\frac{2u^2}{u^2}\,\mathrm du\,\mathrm dv=2\iint_{D'}\mathrm du\,\mathrm dv

where D' is the region D transformed into the u-v plane. The remaining integral is the twice the area of D'.

Now, the integral over D is

\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\left\{\int_0^6\int_{x^2/2}^{x^2}+\int_6^{12}\int_{x^2/2}^{6x}\right\}\frac{\mathrm dx\,\mathrm dy}y

but through the given transformation, the boundary of D' is the set of equations,

\begin{array}{l}y=x^2\implies u^2=u^2v^2\implies v^2=1\implies v=\pm1\\y=\frac{x^2}2\implies u^2=\frac{u^2v^2}2\implies v^2=2\implies v=\pm\sqrt2\\y=6x\implies u^2=6uv\implies u=6v\end{array}

We require that u>0, and the last equation tells us that we would also need v>0. This means 1\le v\le\sqrt2 and 0, so that the integral over D' is

\displaystyle2\iint_{D'}\mathrm du\,\mathrm dv=2\int_1^{\sqrt2}\int_0^{6v}\mathrm du\,\mathrm dv=\boxed6

4 0
3 years ago
What is the volume of this rectangular prisen?<br> Cm<br> 4 cm
Kaylis [27]

Answer:

64 cm

Step-by-step explanation:

Volume = 4 * 4 * 4

             = 64 cm

4 0
3 years ago
Solve the following formula for m v2=3Pmn
Andru [333]

Answer:

m= 0 /(−3np+v2 )

Step-by-step explanation:

8 0
3 years ago
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