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3 years ago

Subtract this problem

Mathematics

1 answer:

Paul [167]3 years ago

3 0

I guess A is the answe

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Georgia spends $39 on gas each week. Approximately how much money does she spend on gas each week?

Pachacha [2.7K]

$40.........................

4 0

4 years ago

Read 2 more answers

#1 2x-16<-18

Evgesh-ka [11]

Answer:

if it's finding x

#1 x<-1

#2 x<4

Step-by-step explanation:

2x-16<-18

add 16 to both sides

2x<-2

then divide 2 to both sides

x<-1

2x-16+4x<8

add like terms

6x-16+<8

add sixteen to both sides

6x<24

divide six to both sides

x<4

5 0

4 years ago

Answer fast please!!!!

MrMuchimi

Answer:

6z + 9

Step-by-step explanation:

distribute 3/4 by 8z to get 6z

distribute 3/4 by 12 to get 9

4 0

3 years ago

Which of following not a way to represent the solution of inequality 5(x + 2) GREATER THAN OR EQUAL TO 7x + 2(x − 1)?

mixer [17]

So because it says NOT a way....I think it's A...Maybe I'm wrong but whatever.

6 0

4 years ago

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The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i

kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

$S=\pi r\sqrt{r^2+h^2}$

and volume,

$V=\frac{1}{3}\pi r^2 h$

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

$f(r,h)=\frac{1}{3}\pi r^2 h$

subject to,

$g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)$

We know for maximum volume $r\neq 0$ . So let $\lambda$ be the Lagranges multipliers be such that,

$f_r=\lambda g_r$

$\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)$

And,

$f_h=\lambda g_h$

$\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}$

$\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)$

Substitute (3) in (2) we get,

$\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)$

$\implies h^2=2r^2$

Substitute this value in (1) we get,

$\pi r\sqrt{h^2+r^2}=8$

$\implies \pi r \sqrt{2r^2+r^2}=8$

$\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252$

Then,

$h=\sqrt{2}(1.21252)\equiv 1.71476$

Hence largest volume,

$V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114$

3 0

3 years ago