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Svetllana [295]
2 years ago
15

(08.03)Heather recorded the different types of music her friends like in the table below:

Mathematics
2 answers:
krok68 [10]2 years ago
4 0

answer:

a)

step-by-step explanation:

the explanation is the picture

**edit** i didn't realize that the words got 'deleted' but here's the order i put them in country, hip-hop, pop, and rock i'm sorry about the inconvinence

good luck :)

i hope this help

brainliest would be highly appreciated

have a nice day!

Ostrovityanka [42]2 years ago
4 0

Answer:

The answer is A.

I took the test and got it right. Hope this helps!

Have a good day :)

~Amy❤

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What are the values that satisfy the trigonometric equation for: 0 ≤ q ≤ 2Π ?
bagirrra123 [75]
Answer: 0, π, 2π

Nevertheless, that is not an option. I see two possibilities: 1) the options are misswirtten, 2) the domain is not well defined.

If the domain were 0 ≤ θ < 2π, then 2π were excluded of the domain ant the answer would be 0, π.

Explanation:

1) The first solution, θ = 0 is trivial:

sin (0) - tan (0) = 0

0 - 0 = 0

2) For other solutions, work the expression:

sin(θ) + tan (-θ) = 0 ← given

sin (θ) - tan(θ) = 0 ← tan (-θ) = tan(θ)

sin(θ) - sin (θ) / cos(θ) = 0 ← tan(θ) = sin(θ) / cos(θ)

sin (θ) [1 - 1/cos(θ)] = 0 ← common factor sin(θ)

⇒ Any of the two factors can be 0

⇒ sin (θ) = 0 or (1 - 1 / cos(θ) = 0,

sin(θ) = 0 ⇒ θ = 0, π, 2π

1 - 1/cos(θ) = 0 ⇒ 1/cos(θ) = 1 ⇒ cos(θ) = 1 ⇒ θ = 0, 2π

⇒ Solutions are 0, π, and 2π

In fact if you test with any of those values the equation is checked. The only way to exclude one of those solutions is changing the domain.
7 0
3 years ago
Read 2 more answers
The statement tan theta -12/5, csc theta -13/5, and the terminal point determined by theta is in quadrant 2."​
Harlamova29_29 [7]

Answer:

Answer C:

Cannot be true because csc(\theta)  is greater than zero in quadrant 2.

Step-by-step explanation:

When the csc of an angle is negative, since the cosecant function is defined as:

csc(\theta)=\frac{1}{sin(\theta)}

that means that the sin of the angle must be negative, and such cannot happen in the second quadrant. The sine function is positive in the first and second quadrant.

Therefore, the correct answer is:

Cannot be true because  csc(\theta)  is greater than zero in quadrant 2.

6 0
3 years ago
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jek_recluse [69]

Answer:

something

Step-by-step explanation:

6 0
3 years ago
Find the slope of the line graphed
Andrej [43]

Answer:

I believe it is 2

7 0
3 years ago
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Factor the common factor out of 8x3 + 12x. please help asap.
Hitman42 [59]
So 8x3 = 24

24 + 12x
the common factor is 12
so you divide everything by 12
24 ÷ 12 = 2
12x ÷ 12 = x

final answer: 12 (2+x)
8 0
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