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konstantin123 [22]
3 years ago
10

How many moles of water h2o are present in 75.0 g h2o?

Chemistry
1 answer:
nikklg [1K]3 years ago
7 0
4.17 moles. Good luck! :)
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Sam believes the rock is more denser than the pencil. He measured the mass of the rock to be 8.5 grams and volume to be 4.5mL. H
mezya [45]

Answer:

Rock

Explanation:

Let's calculate the density of each object:

Rock:

Density = \frac{mass}{volume}=\frac{8.5\ g}{4.5\ mL}=1.9\ g/mL

Pencil:

Density = \frac{mass}{volume}=\frac{2.4\ g}{4.5\ mL}=0.53\ g/mL

Therefore the rock is denser.

6 0
2 years ago
For which of the following activities might you want to hire a chemist?
Basile [38]

Answer:

OPTION (A) : Testing a rock sample for gold content

Explanation:

For testing a rock sample of gold content you will need a Chemist. To test the material, the sample is rubbed on black stone which will leave a mark on the stone. This mark is tested by applying aqua fortis i.e nitric acid on the mark. If the mark gets dissolve then the material is not gold. If the mark sustain the it is further tested by applying aqua regia i.e nitric acid and hydrochloric acid which will prove the sample is of gold if it gets dissolve on using hydrochloric acid. The purity of the sample can be checked by differing the concentration of the aqua regia and comparing it with the gold material of the known purity.

7 0
3 years ago
Read 2 more answers
What functions of cells can be affected by a mutation?
Colt1911 [192]
It changes the rate of growth that cells usually undergo.
6 0
3 years ago
Hợp chất nào có khả năng là hợp chất ion cao nhất ?<br>A Al2O3<br>B ScCl3<br>C NO2<br>D CCl4
Rzqust [24]

Answer:

B

Explanation:

hợp chất nào có khả năng là hợp chất ion cao nhất ?

A Al2O3?

B

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3 years ago
For the balanced equation shown below, if the reaction of 0.112 grams of
Alekssandra [29.7K]

Answer:

The answer is 74.5%.

Explanation:

As we know that % yield=  \frac{actual yield}{theoretical yield} x 100%.

Therefore,

Step 1 Calculate Theoretical yield:

0.112H_{2} x   \frac{1 mol H_{2} }{2.016 g of H{2} }    x    \frac{4 mol H_{2}O }{4 mol H_{2} }    x  \frac{18.02 g H_{2}O }{1 mol H_{2}O}   = 1.001 g H_{2}O

Now Step 2

% yield   =  \frac{actual yield}{theoretical yield} x 100% =   \frac{0.745g}{1.001g} = 74.5%

8 0
3 years ago
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