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konstantin123 [22]
3 years ago
10

How many moles of water h2o are present in 75.0 g h2o?

Chemistry
1 answer:
nikklg [1K]3 years ago
7 0
4.17 moles. Good luck! :)
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A strip of copper 370 μm thick and 4.5 mm wide is placed in a uniform magnetic field B with arrow of magnitude 0.30 T, with B wi
777dan777 [17]

Explanation:

The given data is as follows.

              Magnetic field (B) = 0.30 T

              Current (I) = 24 A

              n = 370 \times 10^{-6} m

            charge on electron (e) = 1.602 \times 10^{-19} C

Formula to calculate the potential difference is as follows.

            V = \frac{B \times I/d}{n \times e
}

                = \frac{0.30 T \times 24 amps}{8.47 \times 10^{28} electrons/ m^{3} \times 370 \times 10^{-6} m \times 1.602 \times 10^{-19} C)}

                = 1.38 \times 10^{-6} V

Therefore, we can conclude that value of potential difference is 1.38 \times 10^{-6} V.

8 0
3 years ago
0.3287 g x 45.2 g =?
murzikaleks [220]

Answer:

The exact answer is 14.85724 grams. Just simply multiply these two numbers together to get your answer in grams. No fancy formula is needed for this! Hopefully this helps!

Feel free to mark brainliest!

4 0
2 years ago
Read 2 more answers
Why is the moon visible?
katrin2010 [14]
It is C. because the sunlight bounces off the moon causing it to be visible only at night.
7 0
3 years ago
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Explain how an automobile air bag protects the people in the car from being hurt as a result of impact
liraira [26]
The quick deployment of the bag which I think is quite similar to a cushion and a balloon. It holds your head/face away from any hard surfaces. Although it does not protect your legs or other extremities that are out of the bags range.
5 0
2 years ago
A chemist must dilute 97.1 ml of aqueous magnesium fluoride solution until the concentration falls to 389 microMolarity . He'll
mojhsa [17]

Answer:

0.302L

Explanation:

<em>...97.1mL of 1.21m M aqueous magnesium fluoride solution</em>

<em />

In this problem the chemist is disolving a solution from 1.21mM = 1.21x10⁻³M, to 389μM = 389x10⁻⁶M. That means the solution must be diluted:

1.21x10⁻³M / 389x10⁻⁶M = 3.11 times

As the initial volume of the original concentration is 97.1mL, the final volume must be:

97.1mL * 3.11 = 302.0mL =

0.302L

6 0
3 years ago
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