1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
borishaifa [10]
3 years ago
9

Provide the names of 2 stars that are dimmer than the Sun and provide their absolute magnitude and type of star.

Chemistry
2 answers:
serg [7]3 years ago
7 0

Answer:rf4rf4rf4f4f

Explanation:

rrf4f45f44f4

Softa [21]3 years ago
5 0

Explanation:

Epsilon Eridani - 3.72

61 Cygni AB - 4.80

You might be interested in
Some of the energy from the sun is reflected or absorbed as it passes through the atmosphere. Middle school science question
kondor19780726 [428]

Answer:

A. true

Explanation:

i.hope it helps u

3 0
3 years ago
Write the following balanced chemical equations for the following reactions.
sleet_krkn [62]

Answer:

2k+2hcl---2kcl+h2

Explanation:

because we have to balance it and in order to balance it we have to make it in equal form

6 0
3 years ago
Consider the reaction of magnesium metal with hydrochloric acid to produce magnesium chloride and hydrogen gas. if 4.40 mol of m
Georgia [21]
The balanced chemical equation for the above reaction is as follows ;
Mg + 2HCl —> MgCl2 + H2
The stoichiometry of Mg to HCl is 1:2
This means that 1 mol of Mg reacts with 2 mol of HCl
Equal amounts of both Mg and HCl have been added. One reagent is the limiting reactant and other reactant is in excess.
Limiting reactant is the reagent that is fully used up in the reaction and the amount of Product formed depends on the amount of limiting reactant present.
In this reaction if Mg is the limiting reactant, 4.40 moles of Mg should react with 4.40x2 -8.80 moles of HCl.
But only 4.40 moles of HCl present therefore HCl is the limiting reactant that reacts with 4.40/2 = 2.20 moles of Mg
Stoichiometry of HCl to MgCl2 is 2:1
Since HCl moles reacted -4.40 mol
Then MgCl2 moles formed are 4.40/2 = 2.20 mol of MgCl2
8 0
4 years ago
A beaker is filled to the 500 mL mark with alcohol. What increase in volume (in mL) does the beaker contain when the temperature
Aliun [14]

Answer:

"1.4 mL" is the appropriate solution.

Explanation:

According to the question,

  • v_0=500
  • \alpha =1.12\times 10^{-4}
  • \Delta \epsilon = 25

Now,

Increase in volume will be:

⇒ \Delta V = \alpha\times v_0\times \Delta \epsilon

By putting the given values, we get

           =1.12\times 10^{-4}\times 500\times 25

           =1.12\times 10^{-4}\times 12500

           =1.4  \ mL

8 0
3 years ago
Using a liquid as a solvent, what could be the state(s) of matter of the solute?
frozen [14]
Solute can be
1) solid -table salt (solute) and water,
2) liquid - alcohol and water,
3) gas - soft drinks -CO2 and water.
8 0
4 years ago
Other questions:
  • 495 cm3 of oxygen gas and 877 cm3 of nitrogen gas, both at 25.0 C and 114.7 kpa, are injected into an evacuated 536 cm3 flask. F
    13·2 answers
  • Given 1.00 grams of each of the following radioisotopes, Ca-37, U-238, P-32 and Rn-222,which would have the least remaining orig
    5·1 answer
  • How many electrons in an atom could have n = 2, l = 1, ml = 0?
    9·1 answer
  • Lysozyme extracted from chicken egg white has a molar mass of 13,930 g mo1-1. Exactly 0.1 g of this protein is dissolved in 50 g
    5·1 answer
  • Three synonyms for introduced species
    10·1 answer
  • Need help on worksheet
    15·1 answer
  • What is the appearance of the signal corresponding to the CH₂ protons in the 1H NMR spectrum of ethyl methyl ether, CH₃CH₂OCH₃?
    10·1 answer
  • Draw the structure of the compound C9H12 from its proton (1H) NMR spectrum below. First-order spin-spin splitting rules and equa
    8·2 answers
  • What is the significance of a gene?Immersive Reader
    12·1 answer
  • During reaction between calcium and oxygen valence electrons
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!