Answer:
Step-by-step explanation:
Total Students = 28
Brown Hair = 22
NOT Brown Hair = 28 - 22 = 6
The probability of an event is the number of that event divided by total number.
So, let denote probability of without brown hair be P(NOT BROWN). So, we can say:
P(NOT BROWN) = 6/28
Reducing, we get:
P(NOT BROWN) = 3/14
Given :
Sunflower produce approximately 50 seeds per flower.
If one ounce of sunflower seeds contain an average of 72 seeds.
To Find :
How many flowers are needed to produce 2 pounds of seeds.
Solution :
1 pound = 16 ounces .
So , 2 pound = 32 ounces .
Number of seeds in 2 pounds of seeds, n = 32×72 = 2304 .
Number of flowers are :
So , approximate number of flower required are 46.
Hence, this is the required solution.
Answer:
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?
90th percentile
The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds