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3 years ago

5

Please read "The lost ship" on storyworks.

1 answer:

Degger [83]3 years ago

7 0

1. it suggests the article could be about the tale of a lost ship, how it became lost, or how it is doing now.
2. could you please provide a picture
3.again, we cannot see a picture
4. we cannot see if the article has a map

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Find the equation of the following line and graph. Through (3,-10) perpendicular to 5x-y=9

enot [183]

bearing in mind that perpendicular lines have negative reciprocal slopes, let's find the slope of 5x - y = 9 then.

$\bf 5x-y=9\implies -y=-5x+9\implies y=\stackrel{\stackrel{m}{\downarrow }}{5}x-9\leftarrow \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{5\implies \cfrac{5}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{5}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{5}}}$

so then, we're really looking for the equation of a line whose slope is -1/5 and runs through (3,-10).

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{-10})~\hspace{10em} slope = m\implies -\cfrac{1}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-10)=-\cfrac{1}{5}(x-3)\implies y+10=-\cfrac{1}{5}x+\cfrac{3}{5} \\\\\\ y=-\cfrac{1}{5}x+\cfrac{3}{5}-10\implies y=-\cfrac{1}{5}x+\cfrac{53}{5}$

and it looks like the one in the picture below.

7 0

3 years ago

NEED HELP ASAP SOMEONE PLEASE!!!!

Alisiya [41]

Answer: The state with the second lowest population has the lowest population density.

Step-by-step explanation:

Since, Density = Population / Area

The population of state A = 1,055,173

Its area = 2677 square km

Thus, the density of state A = $\frac{1055173}{2677}$ = 394.162495,

The population of state B = 1,333,089

Its area = 36,418 square km

Thus, the density of state B = $\frac{1,333,089}{36,418}$ = 36.6052227,

The population of state C = 3,596,677

Its area = 5543 square km

Thus, the density of state C = $\frac{3,596,677}{5543}$ = 648.868302,

The population of state D =6,745,408

Its area = 10555 square km

Thus, the density of state D = $\frac{6,745,408}{10555}$ = 639.072288,

Since, by the above explanation,

The state in increasing order of the populations,

State A < State B < State C < State D,

Also, the state in increasing order of density,

State B < State A < State D < State C

⇒ Second option is correct.

3 0

4 years ago

Kira needs to make color copies of a horse show flyer. The printer can make 24 copies in 1 minute. Kira says the printer makes 1

antoniya [11.8K]

False... It makes 144

7 0

4 years ago

Use the Law of Sines to solve the triangle.<br> 6.) A=60 degrees, a=9, c=10

lesantik [10]

SinA /a = sin C / c
sin 60/9 = sin C / 10
(√3/2)/9 = sinC/ 10
√3/18 = sin C / 10
so c will be sin inverse ((10√3)/10)

8 0

4 years ago

Write the coordinates of the vertices of a triangle A'B'C' that results from a translation of triangle ABC two units to the righ

gayaneshka [121]

Answer:

A'(4,-6) , B'(0,1), C'(-2,-2)

Step-by-step explanation:

From the given graph the coordinates of ΔABC area A (2,-2), B(-2,5) and C(-4,2)

If a translation is applied on ΔABC two units to the right and four units down to create ΔA'B'C'.

Then to find the coordinates of ΔA'B'C' will be we need to apply the translation rule

$(x,y)\rightarrow(x+2,y-4)$

Now, $A(2,-2)\rightarrow A'(2+2,-2-4)=A'(4,-6)$

$B(-2,5)\rightarrow B'(-2+2,5-4)=B'(0,1)$

and $C(-4,2)\rightarrow C'(-4+2,2-4)=C'(-2,-2)$

7 0

4 years ago