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dimulka [17.4K]
4 years ago
10

A system is acted upon by two forces N, and N. What is the net force acting on the system?

Physics
1 answer:
grigory [225]4 years ago
4 0

Answer:

0 ?

assuming the forces are equal they'll cancel each other out

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Express 9.39 x 109 seconds in terms of days
Allisa [31]

                     (9.39 x 10⁹ sec) x (1 day / 8.64 x 10⁴ sec)

                 =    (9.39 / 8.64) x 10⁵ days

                 =        108,680.56 days
4 0
3 years ago
Read 2 more answers
What does the pressure exerted by a gas depend on
pshichka [43]

Answer:

Explanation:

The amount of gas, the volume, and the temperature.

5 0
3 years ago
a basketball player jumped straight up to grab a rebound. If she was in the air for .8 second how high did she jump
Alona [7]
Answer:
0.78m (rounded to nearest hundredth of a meter)

explanation:
time taken for going up=time taken for drop down after reaching the highest point. at the highest point, the velocity becomes 0.

now all thats left is dropping an object from a height (h) and seeing how long it takes to reach the ground. then find out the flight’s total time divided by 2 (0.8/2=0.4)

lets say the velocity is v and the height she jumped to is h. we can make a kinematic expression:
s=vt+½gt²

once we put it all together you should get this:

h=0×0.4+½(9.81) 0.4²


.
∴
Time taken for downward drop
=
0.8
2
=
0.4
s
Suppose that she jumped with initial velocity
=
u

Also suppose that she jumped to a height
h
Using following kinematic expression
s
=
u
t
+
1
2
g
t
2
and inserting various quantities we get
h
=
0
×
0.4
+
1
2
(
9.81
)
0.4
2

h
=
0.78
m
rounded to nearest hundredth of a meter.
5 0
3 years ago
When a surface is illuminated with electromagnetic radiation of wavelength 480 nm, the maximum kinetic energy of the emitted ele
algol [13]

Answer:

Max kinetic energy for 340 nm wavelength will be 2.238\times 10^{-19}j

Explanation:

In first case wavelength of electromagnetic radiation \lambda =480nm=480\times 10^{-9}m

Plank's constant h=6.6\times 10^{-34}J-s

Maximum kinetic energy = 0.54 eV

Energy is given by E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{480\times 10^{-9}}=4.125\times 10^{-19}J

We know that energy is given

E=K_{MAX}+\Phi, here \Phi is work function

So 4.125\times 10^{-19}=0.54\times 10^{-19}+\Phi

\Phi =3.585\times 10^{-19}J

Now wavelength of second radiation = 340 nm

So energy E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{340\times 10^{-9}}=5.823\times 10^{-19}J

So K_{MAX}=5.823\times 10^{-19}-3.585\times 10^{-19}=2.238\times 10^{-19}j

6 0
4 years ago
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