Question

If you toss a ball straight upward at 40 m/s with no air resistance, what will be its speed 2 seconds later? Explain your answer. (Use g = 10 m/s^2)

Answer 1

Answer:

Final speed of the ball, v = 20 m/s.

Explanation:

It is given that,

Initial speed of the ball, u = 40 m/s

Time. t = 2 s

We need to find the speed of the ball after 2 seconds. Let it is denoted by v. It can be calculated using first equation of motion as :

$v=u+a\times t$

Here, a = -g, as the ball is ball is moving under the action of gravity.

$v=u-g\times t$

$v=40-10\times 2$

v = 20 m/s

So, the speed of the ball after 2 seconds is 20 m/s. Hence, this is the required solution.