Question

In triangle RST, RT = 16, ST = 24, and m< R = 120. To the nearest tenth, what is m < s ?

Answer 1

Answer:

m<S = $35.3^{o}$

Step-by-step explanation:

Applying the sine rule to the given question, we have;

$\frac{r}{Sin R}$ = $\frac{s}{Sin S}$

$\frac{24}{Sin 120}$ = $\frac{16}{Sin S}$

cross multiply to have,

16 x Sin 120 = 24  x Sin S

16 x 0.8660 = 24 Sin S

13.856 = 24 Sin S

Sin S = $\frac{13.856}{24}$

         = 0.57733

S = $Sin^{-1}$ 0.57733

  = 35.2630

Thus, m<S = $35.3^{o}$