Roberto overtakes Juanita at the rate of (7.7 mi)/(11 h) = 0.7 mi/h. This is the difference in their speeds. The sum of their speeds is (7.7 mi)/1 h) = 7.7 mi/h.
Roberto walks at the rate (7.7 + 0.7)/2 = 4.2 mi/h.
Juanita walks at the rate 4.2 - 0.7 = 3.5 mi/h.
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In a "sum and diference" problem, one solution is half the total of the sum and difference. If we let R and J be the respective speeds of Roberto and Juanita, we have
R + J = total speed
R - J = difference speed
Adding these two equations, we have
2R = (total speed + difference speed)
R = (total speed + difference speed)2 . . . . . as computed above
Answer:
D
Step-by-step explanation:
ANSWER IS D
Answer:
Answers below
Step-by-step explanation:
7. Area of shape - area of small shape
A(s) = 5*5 = 25 - A(ss) = 3 = 25-3 = 22
8. Area of shape - area of small shape
A(s) = 4*2 = 8 - A(ss) = 1 = 8-1 = 7
(56*a*b)/b= 56a
Remember that multiplying by b and then diving by b cancels out, leaving only 56a left
Final answer: 56a
What is parallel to 2x+5y=8 is B. I am not sure with D because its actually the same with the given equation.
Hope that helps
