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OlgaM077 [116]
3 years ago
15

Donna is leaming about the water cycle in school. She knows that runoff is water that flows over land surfaces,

Physics
1 answer:
77julia77 [94]3 years ago
7 0

Answer:

ummm imma need the picture bud

Explanation:

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What is the name for family labeled #4 (Yellow)?
goldfiish [28.3K]

Answer:

transition metals im sorry if this was too late

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3 years ago
Why does a truck that is traveling in the opposite direction to you on the street appear to be moving faster than it would if yo
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5 0
3 years ago
A 10.0-kg mass is placed on a 25.0o incline and friction keeps it from sliding. The coefficient of static friction in this case
vovangra [49]

The frictional force while the mass is sliding will be 46.2 N.

<h3>What is friction force?</h3>

Opposition forces on the surface cause heat loss during the motion of an object known as the friction force.

Given data:

m(mass)= 10.0-kg

Θ (Inclination angle)=25.0o

Coefficient of sliding friction,\rm \mu_k=0.520

Coefficient of static friction,\rm  \mu_s=0.520

The friction force, F=?

Resolve the force in the inclined plane;

\rm F=\mu_s mg cos25^0 \\\\ F=0.520 \times 10 \times 9.81 \times  cos 25 ^0 \\\\ F= 46.2 \ N

Hence, the frictional force while the mass is sliding will be 46.2 N.

To know more about friction force refer to the link;

brainly.com/question/1714663

#SPJ1

5 0
2 years ago
A glass window 0.33 cm thick measures 87 cm by 36 cm. How much heat flows through this window per minute if the inside and outsi
mojhsa [17]

Answer:

6.38 x 10^4 J

Explanation:

d = 0.33 cm = 0.33 x 10^-2 m, Area = 87 x 36 cm^2 = 0.87 x 0.36 m^2

ΔT = 14 degree C, t = 1 min = 60 second

K = 0.8 W / m K

Heat  = K A ΔT t / d

H = 0.8 x 0.87 x 0.36 x 14 x 60 / (0.33 x 10^-2)

H = 6.38 x 10^4 J

7 0
3 years ago
What is the speed of an object after falling (from rest) a distance of 9.80 meters near the surface of the Earth? Assume air
madam [21]

Hi there!

We can use the kinematic equation:

v_f^2 = v_i^2 + 2ad

vf = Final velocity (? m/s)

vi = initial velocity (0 m/s, dropped from rest)

a = acceleration (due to gravity, 9.8 m/s²)

d = distance (9.8 m)

Simplify the equation to solve for vf:

v_f^2 = 0 + 2ad\\\\v_f = \sqrt{2ad}

Substitute in the given values:

v_f = \sqrt{2(9.8)(9.8)} = \boxed{13.86 m/s}

8 0
2 years ago
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