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7nadin3 [17]
3 years ago
10

Possible answers: A) 336cm B) 110m C) 588m D) 1,029m

Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
6 0

Answer:

\huge\boxed{D)\ 1,029\ m^2}

Step-by-step explanation:

\begin{array}{ccc}4cm&\to&7m\\^{\times7}&&^{\times7}\\28cm&\to&49m\end{array}\\\\\\\begin{array}{ccc}4cm&\to&7m\\^{\times3}&&^{\times3}\\12cm&\to&21m\end{array}

\text{The formula of an area of a rectangle}\ l\times w:\\\\A=l\cdot w\\\\\text{Substitute}\ l=49m,\ w=21m\\\\A=(49)(21)=1,029\ m^2

kozerog [31]3 years ago
5 0

Answer: The area of the enclosure is 1,029 square meters

Step-by-step explanation: The first thing is to use the unit of measurement required by the question, and to do this we need to convert what we have to what is required.

If the scale of the diagram is given as every 4cm represents 7m, that means, every unit of the actual measurement would be given as

(X/4) x 7

For the length of the enclosure, we can determine that as follows;

Length = (28/4) x 7

Length = 7 x 7

Length = 49m

And for the width,

Width = (12/4) x 7

Width = 3 x 7

Width = 21m

Therefore, the area is calculated as,

Area = L x W

Area = 49 x 21

Area = 1029 m²

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Please solve 5 f <br> (Trigonometric Equations)<br> #salute u if u solved it
Zanzabum

Answer:

\beta=45\degree\:\:or\:\:\beta=135\degree

Step-by-step explanation:

We want to solve \tan \beta \sec \beta=\sqrt{2}, where 0\le \beta \le360\degree.

We rewrite in terms of sine and cosine.

\frac{\sin \beta}{\cos \beta} \cdot \frac{1}{\cos \beta} =\sqrt{2}

\frac{\sin \beta}{\cos^2\beta}=\sqrt{2}

Use the Pythagorean identity: \cos^2\beta=1-\sin^2\beta.

\frac{\sin \beta}{1-\sin^2\beta}=\sqrt{2}

\implies \sin \beta=\sqrt{2}(1-\sin^2\beta)

\implies \sin \beta=\sqrt{2}-\sqrt{2}\sin^2\beta

\implies \sqrt{2}\sin^2\beta+\sin \beta- \sqrt{2}=0

This is a quadratic equation in \sin \beta.

By the quadratic formula, we have:

\sin \beta=\frac{-1\pm \sqrt{1^2-4(\sqrt{2})(-\sqrt{2} ) } }{2\cdot \sqrt{2} }

\sin \beta=\frac{-1\pm \sqrt{1^2+4(2) } }{2\cdot \sqrt{2} }

\sin \beta=\frac{-1\pm \sqrt{9} }{2\cdot \sqrt{2} }

\sin \beta=\frac{-1\pm3}{2\cdot \sqrt{2} }

\sin \beta=\frac{2}{2\cdot \sqrt{2} } or \sin \beta=\frac{-4}{2\cdot \sqrt{2} }

\sin \beta=\frac{1}{\sqrt{2} } or \sin \beta=-\frac{2}{\sqrt{2} }

\sin \beta=\frac{\sqrt{2}}{2} or \sin \beta=-\sqrt{2}

When \sin \beta=\frac{\sqrt{2}}{2} , \beta=\sin ^{-1}(\frac{\sqrt{2} }{2} )

\implies \beta=45\degree\:\:or\:\:\beta=135\degree on the interval 0\le \beta \le360\degree.

When  \sin \beta=-\sqrt{2}, \beta is not defined because -1\le \sin \beta \le1

4 0
3 years ago
Can someone help me with my math ?
shepuryov [24]
Easy! Just substitute.

That will be 3 + 8 * 4

Remember PEMDAS? Multiplication comes before addition, so FIRT MULTIPLY.

3+ 32= 35
Final answer= 35
3 0
3 years ago
If you work 8 hours every two days, how many hours will he work in 7 days
zubka84 [21]

Answer:

28 hours for 7 days

Step-by-step explanation:

8/2 =

4

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1 x 7 =

7

7 x 4

28

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6 0
2 years ago
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The radius of a circular field is 70 metres.
NeTakaya

Answer: 439.82

Step-by-step explanation:

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2 years ago
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_________km3 what is the volume of the pyramid
harkovskaia [24]

The volume of the pyramid is 792\ km^3

Explanation:

It is given that the base of the pyramid is a right triangle.

The formula to determine the volume of the pyramid is given by

V=\frac{l w h}{3}

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w is the base width of the pyramid and

h is the height of the pyramid.

From the figure, we can see that,

l=9, w=12 and h=22

Substituting these values in the formula V=\frac{l w h}{3} , we have,

V=\frac{(9)(12)(22)}{3}

Multiplying the numerator, we get,

V=\frac{2376}{3}

Dividing, we get,

V=792

Thus, the volume of the pyramid is 792\ km^3

5 0
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