All categories

3 years ago

Graph the line. Don’t mind the random letters Fghhujhgdfvfdfgvee de f

Mathematics

1 answer:

CaHeK987 [17]3 years ago

8 0

Answer:

Step-by-step explanation:

Here, we want to graph the given line

Mathematically, to graph a line, we will

need to work with the intercepts

The general equation of a straight line is;

y = mx + b

is the slope and b is the y-intercept

with respect to the question, 4 is the y-intercept

we have this point as (0,4)

To get the x intercept, we will need to substitute 0 for the value of y

So, we have ;

0 = -x + 4

x = 4

The x-intercept too is 4

This is the point (4,0)

So by joining the points (0,4) and (4,0);

we have successfully graphed the line

It can be found as an attachment below

You might be interested in

For each handmade card Jacquie sells, she makes a profit of $0.35. In one week she made a profit of $42. she sells the cards for

NARA [144]

Ella hizo 120 tarjetas al venderlas hizo $90 y menos lel beneficio son $48

5 0

4 years ago

During a blind taste test of 8 different sodas, some people were asked to choose a favorite. Each dot represents one person. If

Elena L [17]

Answer:

20:5

Step-by-step explanation:

1. What is the ratio for B and H?

Ratio = 4 to 1 or 4:1

2. What is the question asking?

The question is increasing 5 to 20. What is the quotient of 20 and 5? 4! The question is basically multiplying B by 5. Now, since math is a very jealous subject, it needs to be done on the other side too! So you need to multiply the B, which is 1, by 5.

3. 1 x 5?

4. Answer

So, since B is 20 and H is 5, the ratio would be 20:5!

Hiii, so I REALLY want to rank up, and I just need 4 more Branliests, so if you liked my answer, can you please give me one? Thank you so much, and thanks for the points!!

7 0

3 years ago

Read 2 more answers

When using a one-tailed test and a sample size of 24, what is the probability of a value being to the left of a number that has

UNO [17]

Answer:

P-value = 0.009997

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 24

Nature of test: One-tailed test(Left tailed test)

$t_{\text{statistic}} = -2.50$

We have to calculate the p-value.

Degree of freedom = n - 1 = 23

We calculate the p-value from the table corresponding to t score -2.50 and degree of freedom 23.

P-value = 0.009997

0.009997 is the probability of a value being to the left of a number that has a student-t statistic of –2.50.

3 0

4 years ago

Combine the following sets of terms.<br> I'll give brainiest to first person to answer.

Phoenix [80]

Combining like terms
x^2+4x+1

3 0

3 years ago

Read 2 more answers

a. If cosθ=−45 where θ is in quadrant 3, find sin2θ. b. If cosθ=2√2 where θ is in quadrant 1, find cos2θ. c. If sinθ=817 where θ

sesenic [268]

Answer:

Part A) $sin(2\theta)=\frac{24}{25}$

Part B) $cos(2\theta)=0$

Part C) $tan(2\theta)=-\frac{240}{161}$

Step-by-step explanation:

Part A) we have $cos(\theta)=-\frac{4}{5}$

θ is in quadrant 3 ----> the sine is negative

Find $sin(2\theta)$

we know that

$sin(2\theta)=2sin(\theta)cos(\theta)$

Remember that

$cos^{2} (\theta)+sin^{2} (\theta)=1$

substitute

$(-\frac{4}{5})^{2}+sin^{2} (\theta)=1$

$(\frac{16}{25})+sin^{2} (\theta)=1$

$sin^{2} (\theta)=1-\frac{16}{25}$

$sin^{2} (\theta)=\frac{9}{25}$

$sin(\theta)=-\frac{3}{5}$ ---> remember that the sine is negative (3 quadrant)

Find $sin(2\theta)$

we have

$cos(\theta)=-\frac{4}{5}$

$sin(\theta)=-\frac{3}{5}$

$sin(2\theta)=2sin(\theta)cos(\theta)$

substitute

$sin(2\theta)=2(-\frac{3}{5})(-\frac{4}{5})$

$sin(2\theta)=\frac{24}{25}$

Part B) we have $cos(\theta)=\frac{\sqrt{2}}{2}$

θ is in quadrant 1

Find $cos(2\theta)$

we know that

$cos(2\theta)=2cos^{2} (\theta)-1$

substitute

$cos(2\theta)=2(\frac{\sqrt{2}}{2} )^{2}-1$

$cos(2\theta)=0$

Part C) we have $sin(\theta)=\frac{8}{17}$

θ is in quadrant 2 ----> the cosine is negative

Find $tan(2\theta)$

we know that

$tan(2\theta)=\frac{2tan(\theta)}{1-tan^{2} (\theta)}$

Remember that

$cos^{2} (\theta)+sin^{2} (\theta)=1$

substitute

$cos^{2} (\theta)+(\frac{8}{17})^{2}=1$

$cos^{2} (\theta)=1-\frac{64}{289}$

$cos^{2} (\theta)=\frac{225}{289}$

$cos(\theta)=-\frac{15}{17}$

Find $tan(\theta)$

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

substitute

$tan(\theta)=\frac{(8/17)}{(-15/17)}$

$tan(\theta)=-\frac{8}{15}$

Find $tan(2\theta)$

$tan(2\theta)=\frac{2tan(\theta)}{1-tan^{2} (\theta)}$

substitute

$tan(2\theta)=\frac{2(-\frac{8}{15})}{1-(-\frac{8}{15})^{2}}$

$tan(2\theta)=\frac{(-\frac{16}{15})}{1-(\frac{64}{225})}$

$tan(2\theta)=\frac{(-\frac{16}{15})}{1-\frac{64}{225}}$

$tan(2\theta)=\frac{(-\frac{16}{15})}{\frac{161}{225}}$

$tan(2\theta)=-\frac{240}{161}$

3 0

3 years ago