In the case of a circle, the formula for area, A, is A = pi * r^2, where r is the circle's radius. Since we know that a semicircle is half of a circle, we can simply divide that equation by two to calculate the area of a semicircle. So, the formula for the area of a semicircle is A = pi * r^2/2
5 1/2 * 2 1/3 =
11/2 * 7/3 =
77/6 =
12 5/6 <===
Answer:
no
Step-by-step explanation:
Answer:
![x=\sqrt[3]{10}-2](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B10%7D-2)
Step-by-step explanation:
The composite function (f(x+1)) is moved in the x-axis by -1, you know this by solving x+1=0.
The equivalent expresion for f(x+1) is
Eval the above expression in g(x)
We must find x that gives g(x)=12
The equation is the following
Grouping terms>
To solve for x, must apply cubic root in both sides of equation:
![\sqrt[3]{(x+2)^{3} } =\sqrt[3]{10}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%28x%2B2%29%5E%7B3%7D%20%7D%20%3D%5Csqrt%5B3%5D%7B10%7D)
it then turns in the following>
![x+2=\sqrt[3]{10}\\](https://tex.z-dn.net/?f=x%2B2%3D%5Csqrt%5B3%5D%7B10%7D%5C%5C)
Giving the stated answer
First we should find the base length of the triangle (let's call this y) using Pythagoras' Theorem: c^2 = a^2 + b^2, where c is the hypotenuse and a and b are the other two sides
6^2 = 4^2 + y^2
36 = 16 + y^2
y^2 = 20
y = 4.47 (to two decimal places)
Now this y-value that we have found is actually half of x, which we can see since the length x is perpendicular to h, and thus:
4.47 = 0.5x
x = 4.47/0.5 = 8.9 (to the nearest tenth)
Thus the answer is C
