Given:
Point (7,12) is rotated 1260° counterclockwise about the origin.
To find:
The x-coordinate of the point after this rotation.
Solution:
If a point is rotated 360 degrees then its coordinates remains unchanged.
If a point is rotated 180 counterclockwise about the origin degrees, then
We know that,
After 
rotation the coordinates of points remains same, i.e., (7,12). So, after that (7,12) is rotated 180° counterclockwise about the origin.
The point (7,12) becomes (-7,-12) after rotation of 1260° counterclockwise about the origin.
Therefore, the x-coordinate of the required point is -7.
Answer:
(a) 7 + 3( n - 1 )
(b) 1006
Step-by-step explanation:
ARITHMETIC SEQUENCE.
The number of term of an Arithmetic progression has the formular :
nth term = a + ( n - 1 ) d
a = 7
d = 10 - 7 = 3
nth term = 7 + ( n - 1 ) 3
= 7 + 3n - 3
= 7 + 3( n - 1 )
Therefore,
the nth term of the sequence
= 7 + 3( n - 1 )
(b) For the 1000th term
= 7 + 3 ( 1000-1 )
= 7 + ( 999 )
7 + 999 = 1006
Therefore,
the 1000th term = 1006
Two solutions were found :
u ≥ 2
u ≤ 0
Answer:
the answer is 40 hope this helps you
Answer:
a(10) = 170
Step-by-step explanation:
Given that,
The nth term fo the sequence is :
a(n) = n² + 7n
We need to find the 10th term of the sequence.
Put n = 10 in the above sequence,
a(10) = (10)² + 7(10)
= 100 + 70
= 170
So, the 10th term of the sequence is 170.
