The equations which are true for the values of x given are; x²-4 =0 and 4x²= 16.
<h3>Which equations are true for the values of x?</h3>
The values of x given according to the task content are; x = –2 and x = 2.
By considering equation; x²-4 =0
x² = 4
x = ±2
Also, by considering 4x²= 16;
x² = 16/4 = 4
x = ±4.
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Answer:
Step-by-step explanation:
Comment
This is an arithmetic series. It has the following givens.
a = 27 The first term
d = - 2 The difference between one term and the one behind it.
n = quite small
Tn = a + (n - 1)*d
tn = 27 - 2n + 2
tn = 29 - 2n
Answer:
D) 73.5º
Step-by-step explanation:
Law of sines
sinQ/15 =sin50.1/12
multiply both sides by 15
sinQ = sin50.1/12 * 15
sinQ = 0.958956439769124
Q = arcsin0.958956439769124
Q = 73.5º
Well to set up a substitution equation, you need to make sure you have something you can sub in that's identical in both equations.
we have
3x-y=5
x-4y=-24
what's in common? x and y.
take one of the equations and solve for x or y like so (i'm doing y)
3x-5=y
then substitute the whole 3x-5 equation for y in the second equation. it is quite similar to how you would normally substitute a number like if y=5, then you substitute 5 for y in the second equation, but instead the "5" is an equation "3x-5"
x-4y=-24
x-4(3x-5) = -24
Now that you got it set up, you just need to solve for x and once you got x value, plug the x value in the original equations to find y.