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tino4ka555 [31]
3 years ago
10

Which expression is equivalent to 60 – 3y - 9?

Mathematics
1 answer:
spayn [35]3 years ago
3 0

Answer:

your answer is A

Step-by-step explanation:

:)

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Only need help with the second question. Hope someone can help
DIA [1.3K]

1.11111111111%

did the math hope it helps you out

3 0
3 years ago
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(y^-5)^-10y^10<br><br>the answers are in the image​
fredd [130]

Answer:

\large\boxed{y^{60}}

Step-by-step explanation:

(y^{-5})^{-10}y^{10}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=y^{(-5)(-10)}y^{10}=y^{50}y^{10}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=y^{50+10}=y^{60}

6 0
3 years ago
Sally wants to purchase some snowboarding equipment, clothes, and a season pass. She calculates that it will cost her about $1,8
Sonja [21]

<em><u>Total Cost : 1800</u></em>


<u><em>12 dollars * 16 hours = 192 dollars earned</em></u>


<u><em>0.2 percent * 192 = 38.4 dollars saved</em></u>


A.<u><em>She earns 192 dollars every week</em></u>


B.  she will save <em><u>38.4 dollars * 7 weeks = 268.8 </u></em> dollars in a week.


C.  7 days times 4.3 weeks = 30.1 days. <em><u>30.1 days * 38.4 = 1,155.84 dollars every month.</u></em>


D. it will take her  about <em><u>2 months</u></em> to save the money. <em><u>To be exact: 1.6 months.</u></em>


Hope this helped!

8 0
3 years ago
Suppose a seventh graders birthday is today, and she is 12 years old. How old was she 3 1/2 years ago? Write an equation, and us
german

Answer:

he age of girl 3 \frac{1}{2} years ago is 8.5 years  .

Step-by-step explanation:

Given as :

The present age of seventh grader girl = 12 years

Let The age of her 3 \frac{1}{2} years ago = x years

So The age of girl \frac{7}{2} years ago = x years

<u>Now, According to question</u>

The age of girl 3.5 years ago = 12 - 3.5

Or,  The age of girl 3.5 years ago = 8.5 years

Hence The age of girl 3 \frac{1}{2} years ago is 8.5 years  . Answer

4 0
3 years ago
Evaluate and simplify the following complex fraction
Arisa [49]

Answer:

-0.01851851851

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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