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forsale [732]
3 years ago
9

64 chairs are in a display .1/4 of them are red.how many are red

Mathematics
2 answers:
Brut [27]3 years ago
5 0
16 of them are red :))
san4es73 [151]3 years ago
3 0
Ok, so all you have to do for this is divide 64 by 4!! That equal 16, so 16 of the chairs are red.
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LiRa [457]
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</span><span>distributive property
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</span><span>B.distributive property</span>
7 0
3 years ago
I need help with 5 and 6. May anyone turn them into words? ILL GIVE BRAINLIEST FOR 2 RESPONSES
butalik [34]

Step-by-step explanation:

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5 0
2 years ago
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past
Minchanka [31]
<h2><u>Answer with explanation</u>:</h2>

Let \mu be the distance traveled by deluxe tire .

As per given , we have

Null hypothesis : H_0 : \mu \geq50000

Alternative hypothesis : H_a : \mu

Since H_a is left-tailed and population standard deviation is known, thus we should perform left-tailed z-test.

Test statistic : z=\dfrac{\overlien{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

where, n= sample size

\overline{x}= sample mean

\mu= Population mean

s=sample standard deviation

For n= 31,\ \sigma=8000,\ \overline{x}=46,800\ \&\ s=46,800, we have

z=\dfrac{46800-50000}{\dfrac{8000}{\sqrt{31}}}=-2.23

By using z-value table,

P-value for left tailed test : P(z≤-2.23)=1-P(z<2.23)   [∵P(Z≤-z)=1-P(Z≤z)]

=1-0.9871=0.0129

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[We reject the null hypothesis when p-value is less than the significance level .]

Conclusion : We do not have enough evidence at 0.05 significance level to support the claim that t its deluxe tire averages at least 50,000 miles before it needs to be replaced.

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3 years ago
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zepelin [54]

Answer:

I believe it's 12.

Step-by-step explanation:

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7 0
3 years ago
Please help me with this​
kolbaska11 [484]

Answer:

c

Step-by-step explanation:

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3 0
3 years ago
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