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ss7ja [257]
4 years ago
14

Multiply and simplify: -3ab^3 • (-4a^4b^5)

Mathematics
1 answer:
grandymaker [24]4 years ago
4 0
-3ab^3 * (-4a^4b^5)=\\(-3)(-4)(a^{1+4})(b^{3+5})=\\12a^5b^{8}
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Can someone please find the surface area for me? With work shown? Thank you!
Zanzabum
Surface area is 1/2 pl plus B so find the perimeter of the bottom, times it by 32, and find the area of the base
7 0
3 years ago
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The bottom of a 20-foot ladder is placed 4 ½ feet from the base of a house. To the nearest foot, at what height does the ladder
Oksanka [162]

Answer: 19 ft

Step-by-step explanation:

Hi, since the situation forms a right triangle (see attachment) we have to apply the Pythagorean Theorem:

c^2 = a^2 + b^2

Where c is the hypotenuse of the triangle (in this case the length of the ladder) and a and b are the other sides.

Replacing with the values given:

20^2 = (4 1/2)^2 + x^2

400=20.25 + x ^2

400-20.25 = x^2

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√379.75 = x

x = 19.48

x= 19 ft

Feel free to ask for more if needed or if you did not understand something.

6 0
4 years ago
A box contains 5 red marbles and 7 green marbles. Find the probability of drawing 2 red marbles.
Allushta [10]

Answer:

1) 25/144 or 0.1736

2) 5/33 or 0.1515

Step-by-step explanation:

Total marbles: 5 + 7 = 12

1) 5/12 × 5/12

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2) 5/12 × 4/11

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4 0
3 years ago
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If the hypotenuse of a 45°-45°-90° triangle is 13, what is the length of one of the legs?
stiv31 [10]

Answer:

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Step-by-step explanation:

Using Law of sines to find other two lengths:

a/sinA=b/sinB

let a be length of side unknown and b be hypotenuse then sinB=sin90 and sinA=sin45

a/sin45=13/sin90

a=13sin45

a=13(0.707)

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As the given triangle is isosceles hence the length of other two legs will be same i.e 9.19 !

6 0
3 years ago
A cannon launches a cannonball from a height of 3 feet with an upward velocity of 40 feet per second. The function h=-16t^2+40t+
gavmur [86]
A)  We want to know when h=10 so

10=-16t^2+40t+3

16t^2-40t+7=0

Using the quadratic formula:

t=(40±√1152)/32 

t≈0.189 and 2.311 seconds

So it is at 10 ft twice, about 2/10 of a second when it is rising and at 2 3/10 of a second when it is falling...

b.

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h(1.25)=28ft

So the maximum height of the ball occurs after 1.25 seconds and reaches a height of 28 feet.
3 0
3 years ago
Read 2 more answers
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