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2 years ago

You want to go to the skate park, and you have two options:

Mathematics

1 answer:

Tcecarenko [31]2 years ago

3 0

Answer:

See Explanation

Step-by-step explanation:

Define the variables

Let the entry fee be c and the hourly rate be m

Let the number of hours be x and the total amount be y

Work to solve

For Sami's skate

$c = 6$ and $m = 2$

For Brad's skate

$c =10$ and $m = 1$

The equations

The equation is derived using: $y = mx + c$

For Sami's skate

$y = 2x + 6$

For Brad's skate

$y = x + 10$

When the cost are the same

To do this, we equate both expressions

i.e.

$y = y$

$2x + 6 = x + 10$

$2x -x = 10 - 6$

$x = 4$

i.e. the cost are the same at the 4th hour

What is the cost

Substitute 4 for x in any of the equations

$y = x + 10$

$y = 4 + 10$

$y = 14$

The cost is $14.00

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Diano4ka-milaya [45]

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Answer:

3 1/3

Step-by-step explanation:

Multiply both sides by the reciprocal of the coefficient of c.

(5/2c)(2/5) = (8 1/3)(2/5)

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Answer:

B. Variance = r2 = 0.7225

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cluponka [151]

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3 years ago

PLEASE HELP Given: △KLM LM=12, m∠K=60°, m∠M=45° Find: Perimeter of △KLM.

worty [1.4K]

We have to find the perimeter of the triangle KLM.

We have been given that the length of the side LM=12, $m\angleK=60^\circ$ , and $m\angle M= 45^\circ$

Refer the attached image.

In a triangle sum of three angles should be $180^\circ$ .

So,

$m\angle K+m\angle L+m\angle M=180^\circ$

Plugging the values of angle K and angle M, we get:

$60^\circ+m\angle L+45^\circ=180^\circ$

So,

$m\angle L=180^\circ-105^\circ=75^\circ$

Now, that we have the measure of angle L, we will apply sine rule to find the length of the sides KL and KM.

Using the sine law for the triangle KLM, we get:

$\frac{sin K}{LM}=\frac{sin L}{KM}=\frac{sin M}{KL}$

Refer the image. Plugging the value of the sides of the triangle KLM and the angles of the triangle KLM, we get:

$\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}=\frac{sin 45^\circ}{x}$

Now using,

$\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}$

We get the value of 'y'

$y=\frac{sin 75^\circ}{sin 60^\circ} \times 12=\frac{0.9659}{0.866} \times 12=13.38$

So the length of the side KM is 13.38 units.

Now using,

$\frac {sin 60^\circ}{12}=\frac{sin 45^\circ}{x}$

We get the value of 'x'

$x=\frac{sin 45^\circ}{sin 60^\circ} \times 12=\frac{0.707}{0.866} \times 12=9.79$

So the length of the side KL is 9.79 units.

Now, to find the perimeter of the triangle KLM we need to sum up the length of the sides of the triangle KLM.

The perimeter of the triangle KLM $= KL+ LM + KM = 9.79 + 12 + 13.38 = 35.17$ units

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Answer:

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Step-by-step explanation:

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