The zeros of the polynomial are <span>1, 2, -2 and -3, so this polynomial must have at least one of each of these factors:
(x-1), (x-2), (x-(-2)), and (x-(-3)); rewriting: </span>(x-1), (x-2), (x+2), and (x+3).
Thus, any such polynomial must have a factor (x-1)(x-2)(x+2)(x+3).
The simplest such polynomial we can think of, is p(x)=(x-1)(x-2)(x+2)(x+3).
To write in standard form, lets first multiply the factors two by two as follows:
by the difference of squares formula,
.
Next, we multiply our results:
.
Answer:
Just fill in the problem... 3*-2-1-3*-2
Answer:
36 bulbs
Step-by-step explanation:
$8/4 = $2 each
72.50/2 = 36.25
This is the concept of combination. The number of letter-sequence that are possible to be formed from the letters q,u,a,k,e,s will be evaluated as follows:
Total number of letters is 6
Maximum number of letters in a word is 4
thus the number of four letter sequence that can be formed will be:
6C4
=15
The reason why we are using combination is because no letter can be used more than once in each sequence.
By HL theorem we can conclude that both the triangles are congruent
ΔAED ≅ ΔBEC
<h3>What is HL theorem?</h3>
HL theorem: The Hypotenuse-Leg (HL) Triangle Congruence Theorem is a special case that allows you to show that two right triangles are congruent. If the hypotenuse and a leg of a right triangle are congruent to the hypotenuse and a leg of another right triangle, then the triangles are congruent.
Jackie made a mistake by determining ΔADE is congruent to ΔCBE
we can't conclude it directly because the angles at D and B may be different
∠E=90° and given that hypotenuse of both the triangles are congruent
AD≅CB and leg of the two triangles are congruent AE≅BE
then by HL theorem we can conclude that both the triangles are congruent
ΔAED ≅ ΔBEC
to learn more about HL theorem visit:
brainly.com/question/3914939
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