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3 years ago

Someone pls help I'm confused, I'll give branliest.

Mathematics

1 answer:

IRISSAK [1]3 years ago

5 0

Circle is what it’s showing

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A class writes the equation n + n + 1 + n + 2 = 87 to solve the following problem.

Bess [88]

Answer:

n + n+2 + m+4 = 87

I got this answer.....hope it may helpful

8 0

3 years ago

)The temperature of a city changed by −24 degrees Celsius over a 6-week period. The temperature changed by the same amount each

Vladimir [108]

Average change would be : -24/6
simplified, would be : -4......so the temperature changed -4 degrees every week for 6 weeks

4 0

4 years ago

Read 2 more answers

Find the kilograms in 4000g

ziro4ka [17]

Answer:

4,000,000

Step-by-step explanation:

There are 1,000 grams in a kilogram

So, multiply 4,000 x 1,000

And you get 4,000,000

8 0

3 years ago

Find all solutions in the interval from [0,2pi)<br> 2cos(3x)= -sqrt{2}

algol [13]

Solutions of $2cos(3x)= -\sqrt{2}$ in the interval from [0,2pi) is $x =\frac{\pi}{12}$ and $x = \frac{23\pi}{12}$ .

<u>Step-by-step explanation:</u>

Find all solutions in the interval from [0,2pi)

$2cos(3x)= -\sqrt{2}$

⇒ $2cos(3x)= -\sqrt{2}$

⇒ $\frac{2cos(3x)}{2}= \frac{-\sqrt{2}}{2}$

⇒ $cos3x= \frac{-\sqrt{2}(\sqrt{2})}{2{\sqrt{2}}}$

⇒ $cos3x= \frac{-2}{2{\sqrt{2}}}$

⇒ $cos3x= \frac{-1}{{\sqrt{2}}}$

⇒ $cos^{-1}(cos3x)= cos^{-1}(\frac{-1}{{\sqrt{2}}})$

⇒ $3x=\pm \frac{\pi}{4}$

⇒ $x=\pm \frac{\pi}{12}$

Cosine General solution is :

$x = \pm cos^{-1}(y)+ 2k\pi$

⇒ $x = \pm \frac{\pi}{12}+ 2k\pi$ , k is any integer .

At k=0,

⇒ $x =\frac{\pi}{12}$ ,

At k=1,

⇒ $x = - \frac{\pi}{12}+ 2\pi$

⇒ $x = \frac{23\pi}{12}$

Therefore , Solutions of $2cos(3x)= -\sqrt{2}$ in the interval from [0,2pi) is $x =\frac{\pi}{12}$ and $x = \frac{23\pi}{12}$ .

5 0

3 years ago

Circle the perfect squares

ddd [48]

No circle can never be the perfect squares

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4 years ago