Which one has a larger atomic radius germanium or selenium
2 answers:
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Answer:
The energy of a wave is inversely proportional to the wavelength of the wave.
As wavelength increases, the energy of the wave decreases.
As wavelength decreases, the energy of the wave increases.
Explanation:
The energy of a wave is directly proportional to the wave's frequency. As frequency increases, so does the energy of the wave.
(energy
is proportional to frequency
)
<u>How is this related to wavelength?</u>
Frequency is inversely proportional to wavelength. That means that as frequency increases, wavelength decreases and as frequency decreases, wavelength increases.
(frequency
is inversely proportional to wavelength
)
Therefore, as wavelength increases, the energy of a wave decreases and as wavelength decreases, the energy of a wave increases.
Answer: The balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is .
Explanation:
When a substance tends to gain oxygen atom in a chemical reaction and loses hydrogen atom then it is called oxidation reaction.
For example, chemical equation for oxidation of methane is as follows.
Number of atoms present on reactant side are as follows.
- C = 1
- H = 4
- O = 2
Number of atoms present on product side are as follows.
- C = 1
- H = 2
- O = 3
To balance this equation, multiply by 2 on reactant side. Also, multiply
by 2 on product side. Hence, the equation can be rewritten as follows.
Now, the number of atoms present on reactant side are as follows.
- C = 1
- H = 4
- O = 4
Number of atoms present on product side are as follows.
- C = 1
- H = 4
- O = 4
Since, the atoms present on both reactant and product side are equal. Therefore, this equation is now balanced.
Thus, we can conclude that balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is .