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boyakko [2]
3 years ago
14

PLZ HELP ILL GIVE BRAINLIST!

Chemistry
1 answer:
Schach [20]3 years ago
6 0

Answer:

The energy of a wave is inversely proportional to the wavelength of the wave.

As wavelength increases, the energy of the wave decreases.

As wavelength decreases, the energy of the wave increases.

Explanation:

The energy of a wave is directly proportional to the wave's frequency. As frequency increases, so does the energy of the wave.

E\propto f (energy E is proportional to frequency f)

<u>How is this related to wavelength?</u>

Frequency is inversely proportional to wavelength. That means that as frequency increases, wavelength decreases and as frequency decreases, wavelength increases.

f\propto \frac{1}{\lambda} (frequency f is inversely proportional to wavelength \lambda)

Therefore, as wavelength increases, the energy of a wave decreases and as wavelength decreases, the energy of a wave increases.

E\propto f\propto \frac{1}{\lambda}

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It makes sense just use the stuff that's already in the table. It usually works.

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Read 2 more answers
A) Calculate the osmotic pressure difference between seawater and fresh water. For simplicity, assume thatall the dissolved salt
never [62]

Answer:

a)  Δπ = 1.264 atm

b) W = 128 joules

c)  ΔH >> W  ( a factor greater than 17,000 )

Explanation:

a) The osmotic pressure, π , is determined by :

π = nRT/V, where n= moles of solute

                          R= 0.0821 Latm/kmol

                          T = 300 K

calling π(sw) osmotic pressure for  for sea water and π (fw) for fresh water,

salinity of sea water = 3.5 g / 1L water   (assuming only NaCl for the salts)

salinity of fresh water = 0.5 parts per thousand (range: 0- 0.5 ppt)

πsw = (3.5 g/58.44 g/mol) (0.0821 Latm/Kmol) (300 K ) /1 L = 1.475 atm

πfw = (0.5 g/58.44 g/mol) (0.0821 Latm/Kmol) (300 K ) /1 L = 0.211 atm

d water = 1 g/cm³

Δ π = (1.475 - 0.211) = 1.264 atm

b) W = Δπ V = 1.426 atm x 1L = 1.43 L-atm

1 L-atm = 101.33 j

W =  101.33 j/ Latm x  1.43 Latm = 128 joules

c) ΔH = Q₁ + nΔH vap, where

            Q₁  = heat required to bring the solution from 300 K to boiling, 373 K

            ΔH vap = heat of vaporization

Q = mCΔT = 1000 g x 4.186 j x 73 K = 305.6 j = 0.3056 kj

ΔH vap = (1000 g/ 18 g/mol ) 40.7 kj/mol = 2,261 kj

ΔH =  0.3056 kj + 2,261 kj = 2,261.3 kj

Note = Q << ΔH vap and we could have neglected it.

This result shows why nobody talks about evaporation of sea water to produce fresh water ΔH >> W

6 0
3 years ago
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