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Gennadij [26K]
3 years ago
9

The oceanic crust is mostly associated with the —————.

Chemistry
1 answer:
Lilit [14]3 years ago
4 0
I think it would the hydrosphere
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What are the major parts of the ecosystem
eduard

Answer:

Ecosystems have lots of different living organisms that interact with each other. The living organisms in an ecosystem can be divided into three categories: producers, consumers and decomposers. They are all important parts of an ecosystem. Producers are the green plants.

Explanation:

Hope this helps

4 0
3 years ago
Which of the following values are not equal to 1 mole?
Gekata [30.6K]

Answer:

none of them are equal to one mole

3 0
3 years ago
B. Chlorophenol has three isomers. Draw the skeletal formula for these three isomers and the structural
klemol [59]

Answer:

Explanation:

The image ending 1318 is 2-chlorophenol. The image ending 1725 is 3-chlorophenol and the image ending 1917 is 4-chlorophenol

7 0
3 years ago
The reaction system: POCl3(g) POCl(g) + Cl2(g) is at equilibrium. Which of the following statements describes the behavior of th
mars1129 [50]

Answer: (B) The reverse reaction will proceed to establish equilibrium.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

For the given equation:

POCl_3(g)\leftrightharpoons POCl(g)+Cl_2(g)

Given : when POCl is added to the system

If the concentration of POCl that is the product is increased, so according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease of concentration of POCl takes place. Therefore, the equilibrium will shift in the left or backward direction.

Thus the reaction will shift towards reactants to reestablish equilibrium and thus partial pressure of POCl and Cl_2(g)  decreases and the partial pressure of POCl_3 increases.

8 0
3 years ago
2. Answer the following questions about a sample of calcium phosphate:
weqwewe [10]

Answer:

a) <u>310.18 g/mol</u>

<u>b) 4.352 moles Ca3(PO4)2</u>

<u>c) 2.6 * 10^24 molecules</u>

<u>d) 5.24 * 10^24 P atoms</u>

<u>e)13.056 moles Ca</u>

<u>f)</u>10825.3 grams

Explanation:

Step 1: Data given

Atomic mass of Ca = 40.08 g/mol

Atomic mass of P = 30.97 g/mol

Atomic mass of O = 16.0 g/mol

Step 2: Calculate molecular weight of Ca3(PO4)2

Molecular weight of Ca3(PO4)2 = 3*atomic mass of Ca + 2* atomic mass of P and 8* atomic mass of O

Molecular weight of Ca3(PO4)2 = 3*40.08 + 2*30.97 + 8*16.0  =<u> 310.18 g/mol</u>

Step 3: Calculate moles of Ca3(PO4)2 in 1350 grams

Moles Ca3(PO4)2 = mass Ca3(PO4)2 /molar mass

Moles Ca3(PO4)2 = 1350 grams / 310.18 g/mol

Moles Ca3(PO4)2 = <u>4.352 moles</u>

Step 4: Calculate molecules in 1350 grams

Molecules = moles * number of Avogadro

Molecules = 4.352 moles * 6.02 * 10^23

Molecules = <u>2.6 *10^24 molecules</u>

<u />

Step 5: Calculate moles Phosphorus

For 1 mol Ca3(PO4)2 we need 2 moles P

For 4.352 moles Ca3(PO4)2 we have 2*4.352 = 8.704 moles

Step 6: Calculate P atoms

Atoms P = 8.704 moles * 6.02*10^23

Atoms P =<u> 5.24 * 10^24 P atoms</u>

<u />

Step 7: Calculate moles Calcium in 1350 grams

For 1 mol Ca3(PO4)2 we have 3 moles Ca

For 4.352 moles we have 3*4.352 = <u>13.056 moles Ca</u>

<u />

<u />

<u>Step 8:</u> Calculate mass of 2.1 * 10^25 molecules of Ca3(PO4)2

Moles Ca3(PO4)2 = 2.1 * 10^25 / 6.02 * 10^23

Moles Ca3(PO4)2 = 34.9 moles

Mass Ca3(PO4)2 = 34.9 moles * 310.18 g/mol

Mass Ca3(PO4)2 = 10825.3 grams

4 0
3 years ago
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