The initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.
<em>"Your question is not complete, it seems to be missing the following information;"</em>
the specific heat capacity of the metal is 0.45 J/g⁰C.
The given parameters;
- <em>mass of water, </em>
<em> = 45 g</em> - <em>final temperature of the water, </em>
<em> = 22 ⁰C</em> - <em>mass of the metal, m = 8.5 g</em>
- <em>initial temperature of the metal, t = 82 ⁰C.</em>
- <em>specific heat capacity of the metal, c = 0.45 J/g⁰C.</em>
The initial temperature of the water will be calculated by applying the principle of conservation of energy;
<em>heat gained by water = heat lost by metal</em>
where;
<em>is the specific heat capacity of the water = 4.184 J/g⁰C.</em>
<em />
<em>Substitute the given values;</em>
45 x 4.184 x (22 - t) = 8.5 x 0.45 x (85 - 22)
4142.16 - 188.28t = 240.98
188.28t = 4142.16 - 240.98
188.28t = 3901.18
Thus, the initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.
Learn more here:brainly.com/question/15345295
In an atomic model that includes a nucleus, the negative charge correlates to the electron and is located outside of the positively charged nucleus. It is found in a given region, where there is a probability of electrons to be found called the electron cloud.
Answer:
21.5mL of a 0.100M HCl are required
Explanation:
The sodium phenoxide reacts with HCl to produce phenol and NaCl in a 1:1 reaction.
To solve this question we need to find the moles of sodium phenoxide. These moles = Moles of HCl required to reach equivalence point and, with the concentration, we can find the needed volume as follows:
<em>Mass NaC6H5O:</em>
1.000g * 25% = 0.250g NaC6H5O
<em>Moles NaC6H5O -116.09g/mol-</em>
0.250g NaC6H5O * (1mol/116.09g) = 2.154x10⁻³ moles = Moles of HCl required
<em>Volume 0.100M HCl:</em>
2.154x10⁻³ moles HCl * (1L/0.100mol) = 0.0215L =
<h3>21.5mL of a 0.100M HCl are required</h3>
Is there a question that needs to be answered
