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Vladimir [108]
3 years ago
8

What explains the change in ionization energy that occurs between removing the first and second electrons from an atom

Chemistry
1 answer:
Jobisdone [24]3 years ago
5 0
Options are as follow,

A. The ionization energy decreases because the ratio of the protons to electrons increases.
B. The ionization energy increases because the ratio of the protons to electrons increases.
C. The ionization energy decreases because the ratio of the protons to electrons decreases.
<span>D. The ionization energy increases because the ratio of the protons to electrons decreases.
</span>
Answer:
            Option-B (The ionization energy increases because the ratio of the protons to electrons increases).

Explanation:
                  Ionization energy is the amount of energy required to remove one electron from the valence shell of an atom.
                  Also, first IE is energy required for removing electron from neutral atom, 2nd IE is energy required for is for removing electron from a mono positive atom and so on.
                  Example:
                                  1st IE of Na is 495.8 kJ/mol

                                   2nd IE of Na is 4562.4 kJ/mol

Second ionization energy is greater because after the removal of first electron the ratio of protons to electrons increases, resulting in more nuclear effect. Also, the second IE is greater because the Na⁺ having noble gas configuration is a stable state, hence more energy is required to knock out electron from it.
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Free-energy change, ΔG∘, is related to cell potential, E∘, by the equation ΔG∘=−nFE∘ where n is the number of moles of electrons
elena-s [515]

Answer:

-372000 J or -372 KJ

Explanation:

We have the electrochemical reaction as;

Mg(s)  +  Fe^2+(aq)→  Mg^2+(aq)  +   Fe(s)

We must first calculate the E∘cell from;

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E∘anode = -2.37 V

Hence;

E∘cell = -0.44 V -(-2.37 V)

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4 0
3 years ago
How many moles of solute are contained in a 250.0-milliliter solution that has a concentration of 0.85 M?
adoni [48]

Answer : The correct option is, 0.21 moles

Solution : Given,

Molarity of the solution = 0.85 M = 0.85 mole/L

Volume of solution = 250 ml = 0.25 L     (1L=1000ml)

Molarity : It is defined as the number of moles of solute present in one liter of the solution.

Formula used :

Molarity=\frac{\text{moles of solute}}{\text{Volume of solution in liters}}

Now put all the given values in this formula, we get the moles of solute of the solution.

0.85mole/L=\frac{\text{moles of solute}}{0.25L}

\text{moles of solute}=0.2125=0.21moles

Therefore, the moles of solute is, 0.21 moles

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3 years ago
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