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Vladimir [108]
3 years ago
8

What explains the change in ionization energy that occurs between removing the first and second electrons from an atom

Chemistry
1 answer:
Jobisdone [24]3 years ago
5 0
Options are as follow,

A. The ionization energy decreases because the ratio of the protons to electrons increases.
B. The ionization energy increases because the ratio of the protons to electrons increases.
C. The ionization energy decreases because the ratio of the protons to electrons decreases.
<span>D. The ionization energy increases because the ratio of the protons to electrons decreases.
</span>
Answer:
            Option-B (The ionization energy increases because the ratio of the protons to electrons increases).

Explanation:
                  Ionization energy is the amount of energy required to remove one electron from the valence shell of an atom.
                  Also, first IE is energy required for removing electron from neutral atom, 2nd IE is energy required for is for removing electron from a mono positive atom and so on.
                  Example:
                                  1st IE of Na is 495.8 kJ/mol

                                   2nd IE of Na is 4562.4 kJ/mol

Second ionization energy is greater because after the removal of first electron the ratio of protons to electrons increases, resulting in more nuclear effect. Also, the second IE is greater because the Na⁺ having noble gas configuration is a stable state, hence more energy is required to knock out electron from it.
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To name the compound written as CuCl2, you would write:
vovangra [49]

Answer: option C. Copper (II) chloride

Explanation:

To name CuCl2, we need to know the oxidation state of Cu in the compound as chlorine always have oxidation on —1 in all its compound. The oxidation state of Cu can be calculated as follows:

Cu + 2Cl = 0 (since the compound has no charge)

Cl = —1

Cu + 2(—1) = 0

Cu —2 = 0

Collect like terms

Cu = 0 +2

Cu = +2

Therefore, the oxidation state of Cu in CuCl2 is +2.

The name of the compound will be copper(ii) chloride, since cupper has oxidation state +2 in the compound.

4 0
3 years ago
What type of radioactive decay will the isotopes 13B and 188Au most likely undergo?
scoundrel [369]

Answer:

b. Beta emission, beta emission

Explanation:

A factor to consider when deciding whether a particular nuclide will undergo this or that type of radioactive decay is to consider its neutron:proton ratio (N/P).

Now let us look at the N/P ratio of each atom;

For B-13, there are 8 neutrons and five protons N/P ratio = 8/5 = 1.6

For Au-188 there are 109 neutrons and 79 protons N/P ratio = 109/79=1.4

For B-13, the N/P ratio lies beyond the belt of stability hence it undergoes beta emission to decrease its N/P ratio.

For Au-188, its N/P ratio also lies above the belt of stability which is 1:1 hence it also undergoes beta emission in order to attain a lower N/P ratio.

8 0
3 years ago
Which statement is correct with respect to gross primary productivity
bezimeni [28]
Gross primary production and net primary production. Gross primary production is the amount of chemical energy as biomass that primary producers create in a given length of time.
8 0
3 years ago
An unknown substance has a mass of 14.7 g . When the substance absorbs 1.323×102 J of heat, the temperature of the substance is
Fudgin [204]
The correct answer of the given question above would be option B. IRON 0.449. Based on the given details above about an unknown substance that has a mass of 14.7 g and  the substance absorbs 1.323×102 J of heat, the temperature of the substance is raised from 25.0 ∘C to45.0 ∘C, most likely, the substance is IRON. Hope this answers the question.
7 0
4 years ago
Read 2 more answers
PLEASE HELP WILL GIVE BRAINLEST
aliina [53]

Answer:

Option A.

Lower air pressure results in a lower boiling point

Explanation:

This is because in an open system, the lower the pressure the lesser the energy that will be required for boiling point. The is little or no collision of air molecules with the surface of the liquid

But if there is increase in pressure, more energy will be required to get to boiling point because there will be strong collision between air molecules and surface of the liquid.

8 0
3 years ago
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