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Vladimir [108]
3 years ago
8

What explains the change in ionization energy that occurs between removing the first and second electrons from an atom

Chemistry
1 answer:
Jobisdone [24]3 years ago
5 0
Options are as follow,

A. The ionization energy decreases because the ratio of the protons to electrons increases.
B. The ionization energy increases because the ratio of the protons to electrons increases.
C. The ionization energy decreases because the ratio of the protons to electrons decreases.
<span>D. The ionization energy increases because the ratio of the protons to electrons decreases.
</span>
Answer:
            Option-B (The ionization energy increases because the ratio of the protons to electrons increases).

Explanation:
                  Ionization energy is the amount of energy required to remove one electron from the valence shell of an atom.
                  Also, first IE is energy required for removing electron from neutral atom, 2nd IE is energy required for is for removing electron from a mono positive atom and so on.
                  Example:
                                  1st IE of Na is 495.8 kJ/mol

                                   2nd IE of Na is 4562.4 kJ/mol

Second ionization energy is greater because after the removal of first electron the ratio of protons to electrons increases, resulting in more nuclear effect. Also, the second IE is greater because the Na⁺ having noble gas configuration is a stable state, hence more energy is required to knock out electron from it.
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If 5.65 grams of zinc metal react with 21.6 grams of silver nitrate, how many grams of silver metal can be formed and how many g
Igoryamba
The balanced chemical reaction is:

Zn + 2AgNO3 =  Zn(NO3)2 + 2Ag

To determine the amount of the reactant left, we have to determine which is the limiting and the excess reactant. We do as follows:

5.65 g Zn ( 1 mol / 65.38 g) = 0.09 mol Zn
21.6 g AgNO3 (1 mol / 169.87 g) = 0.13 mol AgNO3

The limiting reactant would be silver nitrate since it is consumed completely in the reaction. The excess reactant would be zinc. 

Excess Zinc = 0.09 mol Zn - (0.13 / 2) mol Zn = 0.025 mol Zn left
7 0
4 years ago
Read 2 more answers
What should be the temperature of the solvent before adding it to the sample to be recrystallized?
Serhud [2]

Answer:

Near the boiling point of the solvent

Explanation:

The process of recrystallization is hinged on the fact that the amount of solute that can be dissolved by a solvent increases with temperature. The process involves creation of a solution by dissolving a solute in a solvent at or near its boiling point.  At the boiling point of the solvent, the solute has a greater solubility in the solvent; not much volume of  the hot solvent is required to dissolve the solute.

Before the solution is later cooled, you can now filter out insoluble impurities from the hot solvent. The quantity of the original solute drops appreciably because impurities have been removed. At this lower temperature, the solution becomes saturated and the solute can no longer be held in solution hence it forms pure crystals of solute, which can be recovered.

Recrystallization must be carried out using the proper solvent. The solute must be relatively insoluble in the solvent at room temperature but more soluble in the solvent at elevated temperature.

3 0
3 years ago
Is 2Zn + 2HCI = ZnCL2 + H2 balanced or unbalanced
riadik2000 [5.3K]
Unbalanced it should be 2Zn+2Hcl=2ZnCl2+H2
7 0
3 years ago
The solution you identified in question (1) acts as a buffer due to reactions that occur within the solution when an acid or a b
weeeeeb [17]

Answer:

The answer is "\bold{CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)}"

Explanation:

When HCI is added in the chemical equation it reacts with sodium acetate so, it will give the following chemical equation:

CH_3COONa\ (aq) + HCl\ (aq)\longrightarrow CH_3COOH\ (aq) + NaCl\ (aq)\\\\

 In this, the CH_3COOH is a weak acid so, it not completely dissociated.

CH_3COONa \ (aq) \ \ and \ NaCl were strong electrolytes they are completely dissociated.

The HCl is a strong acid so, it is completely dissociated So, the net ionic equation is:

CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)

8 0
3 years ago
What is the molarity of 20.2 g of potassium nitrate, KNO3, in enough water to make 250.0 mL of solution
KATRIN_1 [288]

Answer:

0.8M

Explanation:

CM=n/V

8 0
3 years ago
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